4.1 The aluminum rod AB (Gal = 27 GPa) is bonded to the brass rod BD (Gbr = 39 GPa). The portion CD of the brass rod is hollow and has an inner diameter of 40 mm. If the allowable shear stresses for the aluminum and brass are 90 MPa and 70 MPa, respectively, and the allowable angle of twist of the free end A is 6 degrees, determine the maximum permissible value of T.

Q: (1) and (2). Bar (1) is a 30-in.-long bronze [E = 15900 ksi, α= 9.4 × 10−6/°F] bar with a…

A: Determine:(a) the normal stresses in bars (1) and (2).(b) the normal strains in bars (1) and (2).(c)…

Q: Find

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Q: Determine the gross area of steel needed to design the bar force members at BC, BE, and AE. Stress…

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A: Given data- A structural steel member- Simple tension-σy=280 N/mm2Principal stress-σ1=122 N/mm2…

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Q: Compound axial member ABC has a uniform diameter of d = 1.25 in. • Segment (1) is an aluminum [E, =…

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Q: A rigid bar AB is pinned at end A and issupported by a wire CD and loaded by a force P atend B (see…

A: Given:- E = 210 GPa σY =820 MPa L =1.0 m diameter is d =3 mm To find:- (a) Assuming n = 0.2,…

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A: Modified Goodman criterion : The Goodman relation (also known as a Goodman diagram, a Goodman-Haigh…

Q: Compute the deformation in member 1 which is solid alumnim with a area of 214159 mm^2

A: Given Loads 4, 10, 12 and 8 kNSpan Diameter of section 1 = 20 mmElasticity modulus of section 1 = 70…

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Q: Bar FA in the pin-connected structure below is to be considered rigid and is horizontal before loads…

A: Given that : Properties of member BC : E = 75 GPa Cross sectional area = 1000 mm2 Properties of…

Q: Total deformation Can be ab teined by in tegratug dx %3D ds %3D Wzt Wi -WZ.x

A: Integrate to get axial deformation formula δ=∫dδ=PE∫0Ldxw2+w1-w2Lxt2+t1-t2Lx

Q: What is the assumption of an axial force member? * Elongate the member - Tensile Force (T)(+)…

A: Ans = A,D A negative axial member force implies that member is in compression (shorten the member)…

Q: El is constant, find the reaction forces. Using the method of consistent deformations

A: Calculation of Reactions at Supports using method of consistent deformation or Force method of…

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Q: A small aluminum alloy [E = 62 GPa] tee shape is used as a simply supported beam as shown. For this…

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Q: 1. See figure below and solve for the maximum value of torque the composite shaft can accommodate…

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Q: Asmall aluminum alloy [E = 74 GPa] tee shape is used as a simply supported beam as shown. For this…

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Q: The method of consistent deformation is also known as: O Force Method O Unit load Method O Three…

A: Method of consistent deformation is one of the  method to analyze the  indeterminate structures.

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Q: -200mm- -300mm- -- Aluminum E=70 GPa A=900 mm? Steel E=200 GPa A=1200 mm?

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Q: (a) Determine the magnitude of load P that can safely be applied to the structure if a minimum…

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Q: The pin-connected structure consists of a rigid beam ABCD and two supporting bars. Bar (1) is an…

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Q: If the steel has a stress of A100 = 100 ksi, what is the gross area of the steel required to design…

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Q: When the normal stresses are at their maximum or minimum values, the shear stresses are zero. We can…

A: 1- Yes when normal stresses are maximum or minimum, then at that element shear stress is zero. 2-…

Q: Knowing that each rod is solid and has a d twist (a) at B, (b) at C. A m - Brass B Aluminum m C 100…

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Q: У L

A: Given:- y=x3-xL To find:- curvature of the beam at themid-span

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Q: Stresses at any point in a simple axial member do not depend on the orientation of the plane being…

A: False The stress at a point in a body subjected to axial force depend on the inclination of the…

Q: Q- The normal stresses on the two mutually perpendicular planes at a point are 120 MPa (Tensile) and…

A:

Q: . Bronze pipe (1) has an elastic modulus of E1 16,000 ksi, a cross-sectional area of A1 2.68 in m…

A: Given data ∆=0.25 inPipe 1                                            Pipe 2E1=16000 Ksi…

Q: The rigid bar of ABCD of negligible weight is supported hinge at A, steel rod at B and bronze rod at…

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Q: A small aluminum alloy [E = 76 GPa] tee shape is used as a simply supported beam as shown. For this…

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Q: Steel bar of cross-section 550mm2 is acted upon by the forces shown in figure. For steel, E =…

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Q: The aluminum rod AB (Gaj = 27 GPa) is bonded to the brass rod BD (Gpr = 39 GPa). The portion CD of…

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Q: The brass wire has a triangular cross section, 2mm on a side. The yield stress for brass is Ty= 208…

A: For triangular beam the torsion is given as τmax=20Ta3τmax=20Ta3

Q: H.W 3 Two aluminum alloy plates (2) are attached to the sides of a wooden beam (1) as shown in…

A: Solution: Given data: b1=80 mmd1=240 mmb2=10 mmd2=120 mma=60mmE1=12.5 GpaE2=70 Gpa Calculation:…

British Gravitational Bg System Of Units

Measuring is the comparison of a particular physical quantity with its reference value. A unit is a fixed physical quantity. The length is a physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.