4. Write a recursive algorithm in pseudocode that finds the lowest common ancestor (LCA) of two given nodes in a binary tree T. The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself). If either p or q is null, the LCA is null. For this problem, Nodes have left, right, and parent references as well as a field called level which stores the level of the node in the tree. In the sample tree below, node 5 is on level 0, while nodes 4 and 6 are on level 1. Write your solution here. 5 / \ 4 <- level 0 6 < level 1 function lowest_common_ancestor (Node p, Node q)

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4. Write a recursive algorithm in pseudocode that finds the lowest common ancestor (LCA) of two
given nodes in a binary tree T. The lowest common ancestor is defined between two
nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node
to be a descendant of itself). If either p or q is null, the LCA is null. For this problem, Nodes have
left, right, and parent references as well as a field called level which stores the level of the
node in the tree. In the sample tree below, node 5 is on level 0, while nodes 4 and 6 are on level 1.
Write your solution here.
5 <- level 0
4 6 < level 1
function lowest_common_ancestor (Node P,
Node q)
Transcribed Image Text:4. Write a recursive algorithm in pseudocode that finds the lowest common ancestor (LCA) of two given nodes in a binary tree T. The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself). If either p or q is null, the LCA is null. For this problem, Nodes have left, right, and parent references as well as a field called level which stores the level of the node in the tree. In the sample tree below, node 5 is on level 0, while nodes 4 and 6 are on level 1. Write your solution here. 5 <- level 0 4 6 < level 1 function lowest_common_ancestor (Node P, Node q)
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