4. What would be the phenotypes, phenotypic ratio, and gen kids, if the mother is heterozygous freckled and tall while the and heterozygous tall? itcı TalL(T) th fuoclkkles (r
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- 1. What percentage of the offspring will have a homozygous recessive genotype? Gray fur White fur 2. What will be the ratio of gray fur to white fur in the offspring? Gg x gg 3. What percentage of the offspring will have a tall phenotype? t. Tall Short 4. What percentage of the offspring will have a homozygous recessive genotype? TT tt 5. What percentage of the offspring will have white eyes? White eyes Dark eyes 6. What percentage of the offspring will have a heterozygous genotype? 7. What percentage of the offspring will4. In humans, brown eye color (B) is dominant to blue eye color (b). A woman who is homozygous dominant has children with a heterozygous man for this trait. Complete a Punnett Square and report the genotypic and phenotypic ratios of their possible children in the space provided.2. One parent is homozygous dominant and the other heterozygous dominant for chin fissure gene. NOTE: chin fissure is a dominant trait F smooth chin is a recessive trait f Mom's genotype? A. Probability that child will have a chin fissure? Dad's genotype? B. Probability that child will be homozygous dominant for a chin fissure? C. Probability that child will be heterozygous dominant for a chin fissure? D. Probability that child will be homozygous recessive for a smooth chin? 7
- 1. If one parent is homozygous dominant for a trait, that parent's genotype might be GG. If the other parent is homozygous recessive for the same trait, that parent's genotype would be gg. What are the possible genotypes of their offspring? b. How many different phenotypes might we possibly see in their offspring? 2. If a male is homozygous dominant for a trait, that parent's genotype might be DD. If the female is heterozygous for the same trait, her genotype would be Dd. a. How many genetically different sperm can the male produce? b. Using a Punnett square, determine the expected genotypic ratios of their offspring. What are the expected phenotypic ratios? 3. In garden peas, the gene for red flowers (R) is dominant over the gene for white flowers (r). If pollen (cells containing sperm nuclei) from the anther (male reproductive organ) of a homozygous red-flowered plant is added to the pistil (female reproductive organ containing the egg) of a white- flowered plant: a. c. What would be…3. Black coat (B) color in Cocker Spaniels is dominant, while red coat (b) color is recessive; solid pattern (S) is dominant, while spotted (s) pattern is recessive. Create a Punnett square that shows all of the possible offspring of a solid black male (BBSs) mated to a solid red female (bbSs). Include the percentage/ratio of occurrence for each phenotype. Include the percentage/ratio of occurrence for each phenotype.1. Muscular dystrophy is an x linked recessive disorder. If two of the four offsprings have muscular dystrophy and the other two are normal, predict the genotype of the parents. The offsprins are all boys and the parents appear normal. 2. At age 50, the girl is bald and the boy is not bald. They are twins. What is the genotype of the girl? Predict the genotype of the parents of the twins.
- 3. Two yetis have babies. a. What is the dominant phenotype? b. What is the recessive phenotype? c. What is the genotype of the yeti parent on the left? d. What are the two possible genotypes of the yeti parent on the right? e. What are the phenotypes of the yeti babies? f. Complete both Punnett Squares below, one each for both possible genotypes of the right adult yeti. 8. Circle the Punnett Square above that is correct for the yetis shown here. h. What are the genotypes of the parents? i. Why can't the parents have a different genotype? (assume that the offspring exactly follow the predicted ratios) Agricultural Sciences COPYRIGHT CRAIG KOHN, WATERFORD WI 2011. AVAILABLE FOR PUBLIC USE PROVIDED THE AUTHOR IS CITED.16. A couple has two children; one with a widow's peak and one without. If both parents have a widow's peak what do you know to be true? 1. Both parents are heterozygous for the trait 2. Both parents are homozygous dominant for the trait 3. Both parents are homozygous recessive 4. One parent is homozygous dominant the other is homozygous recessive5. SpongeBob SquarePants recently met SpongeSusie Roundpants at a dance. SpongeBob is heterozygous for his square shape, but SpongeSusie is round. Create a Punnett square to show the possibilities that would result if SpongeBob and SpongeSusie had children. 1. List the possible genotypes of the offspring: Shape: Square (S), round (S). 2. List the possible phenotypes of the offspring: A Genotype for SpongeBob:SS B Genotype for SpongeSusie SS C. Complete the Punnett Square 3. What are the chances of having an offspring with square shape: S S out of or %. 4. What are the chances of having an offspring with round shape: out of or %. 5. What is the ratio of square to round shape? SI
- 10. If B=brown eyes and b=blue eyes, and a man with brown eyes and a woman with blue eyes have a child with blue eyes, what is the genotype of the man for eye color? Assume complete dominance. * BB ВB or Bb Bb brown can't tell without more information5. Both parents are heterozygous (Mm x Mm) a. Part A (fill in the boxes): M m M b. Part B (fill in the boxes): Total number of offspring with the heavily muscled phenotype Proportion and percent of heavily muscled offspring Total number of offspring with the in-between phenotype Proportion and percent of in-between offspring Total number of offspring with typical muscles Proportion and percent of typical muscled offspring Total: 100%4. In pea plants, the round shape (R) is dominant over wrinkled shape (r) for seed shape and tall (T) is the dominant allele in plant height. Parents heterozygous for both traits are cross- pollinated. Determine the frequency for the four different phenotypes of the offspring. Parental Gametes: Tall plant, round shape seeds: Tall plant, wrinkled shape seeds: Short plant, round shape seeds: Short plant, wrinkled shape seeds: 5. Dianne is married to Enzo, and they have four children. Dianne has a straight nose (recessive) and can roll her tongue (dominant). Enzo can roll his tongue, but he has a convex (Roman) nose (dominant). Of their four children, Peter is just like his father, and Leah is just like her mother. The other children-Anna, who has a convex nose, and Alex, who has a straight nose-are unable to roll their tongues. Please answer the following questions about this family. a. What are the genotypes of Dianne and Enzo? b. What is the genotype of the following? i. Peter: ii.…