4. What fraction of 5.00 MeV a particles will be scattered through angles greater than 8.00° from a gold foil (Z = 79, density = 19.3 g/cm³) of thickness 10-8 m?
4. What fraction of 5.00 MeV a particles will be scattered through angles greater than 8.00° from a gold foil (Z = 79, density = 19.3 g/cm³) of thickness 10-8 m?
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Transcribed Image Text:**Question:**
What fraction of 5.00 MeV α particles will be scattered through angles greater than 8.00° from a gold foil (Z = 79, density = 19.3 g/cm³) of thickness \(10^{-8}\) m?
**Explanation:**
This problem involves calculating the fraction of alpha particles (α particles) that are scattered at angles greater than 8.00° after passing through a thin gold foil.
- **MeV** (Mega electron-Volt) refers to the energy of the α particles.
- **Z = 79** signifies the atomic number of gold, which is essential for determining its scattering properties.
- **Density = 19.3 g/cm³** provides information about the material that influences how particles are scattered.
- **Thickness \(10^{-8}\) m** refers to the extremely thin layer of gold foil that the α particles traverse.
To solve this, one typically uses the Rutherford scattering formula, which is applicable in nuclear physics for predicting the scattering angles of charged particles after interacting with a nucleus.
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