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Question 4! This is applied thermodynamics (think of degrees of freedom)! I could really use your help with this! Thank you

4. Two different gas samples have the same temperature. One of the samples consists
of dry air. The other consists of water vapor. Assuming m/N is the same in both cases,
which gas has the higher RMS velocity? Explain.

Expert Solution

Step 1

RMS velocity of gaseous sample is

V_RMS= $\sqrt{3 R T / M_{O}}$

Where M_O is molar mass of gas.(kg/mol)

if m/N= is molar mass/mole

if its is same for both samples

then RMS velocity will be same for both.

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