4 **Problem 4: Reaction Mechanism and Product Identification**The following series of reactions involves two intermediates (A & B) and a final product (C). The task is to draw the major and target products for each reaction and explain the mechanism leading to the product.**Reaction Steps:**1. **Starting Material:** - A dibromo compound is provided as the starting material.2. **First Reaction:** - Reagent: Excess Sodium Amide (xs NaNH₂) - Intermediate A is formed after the elimination of bromine atoms.3. **Second Reaction:** - Reagent: Ethyl Iodide - Intermediate B is formed via nucleophilic substitution or addition.4. **Final Reaction:** - Reagent: 1 Equivalent of Hydrogen Bromide (1 eq HBr) - Product C is formed, potentially restoring or altering the structure to produce the final target compound.You are expected to illustrate each major intermediate and final product, providing a detailed explanation of the mechanism by which each transformation occurs.

NaNH2 is a strong base that converts dibromide to alkyne by abstraction of proton

4. The following series of reactions has two intermediates (A & B) and a final product (C). Draw the major and target product from each reaction. Then show the mechanism that leads to the product. Br xs NaNH, 1 eq HBr Br A B

4. The following series of reactions has two intermediates (A & B) and a final product (C). Draw the major and target product from each reaction. Then show the mechanism that leads to the product. Br xs NaNH, 1 eq HBr Br A B

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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