4. The combustion of toluene (C7H8) has a heat of reaction of -3.91 x 103 kJ/mol. When 1.55g toluene undergoes combustion in a bomb calorimeter, the temperature rises from 23.12°C to 37.57°C. Find the heat capacity of the bomb calorimeter.

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**Combustion of Toluene in a Bomb Calorimeter**

In this problem, we explore the combustion of toluene (C₇H₈), which has a heat of reaction of -3.91 x 10³ kJ/mol. When 1.55 g of toluene undergoes combustion in a bomb calorimeter, the temperature rises from 23.12°C to 37.57°C. The task is to find the heat capacity of the bomb calorimeter.

To solve this, we can use the formula:

\[ q = C \times \Delta T \]

Where:
- \( q \) is the heat released.
- \( C \) is the heat capacity of the calorimeter.
- \( \Delta T \) is the change in temperature (37.57°C - 23.12°C).

Given:
- Heat of reaction = -3.91 x 10³ kJ/mol (energy released per mole).
- Mass of toluene = 1.55 g.
- Molecular weight of toluene (C₇H₈) = 92.14 g/mol.

Calculate the moles of toluene:

\[ \text{Moles of toluene} = \frac{\text{Mass}}{\text{Molecular weight}} = \frac{1.55 \, \text{g}}{92.14 \, \text{g/mol}} \]

Next, calculate the total heat released using the moles from above and the heat of reaction.

Finally, use the total heat released and the temperature change to find the heat capacity:

\[ C = \frac{q}{\Delta T} \]

This problem demonstrates the process of calculating thermal properties using experimental data from a calorimetric experiment.
Transcribed Image Text:**Combustion of Toluene in a Bomb Calorimeter** In this problem, we explore the combustion of toluene (C₇H₈), which has a heat of reaction of -3.91 x 10³ kJ/mol. When 1.55 g of toluene undergoes combustion in a bomb calorimeter, the temperature rises from 23.12°C to 37.57°C. The task is to find the heat capacity of the bomb calorimeter. To solve this, we can use the formula: \[ q = C \times \Delta T \] Where: - \( q \) is the heat released. - \( C \) is the heat capacity of the calorimeter. - \( \Delta T \) is the change in temperature (37.57°C - 23.12°C). Given: - Heat of reaction = -3.91 x 10³ kJ/mol (energy released per mole). - Mass of toluene = 1.55 g. - Molecular weight of toluene (C₇H₈) = 92.14 g/mol. Calculate the moles of toluene: \[ \text{Moles of toluene} = \frac{\text{Mass}}{\text{Molecular weight}} = \frac{1.55 \, \text{g}}{92.14 \, \text{g/mol}} \] Next, calculate the total heat released using the moles from above and the heat of reaction. Finally, use the total heat released and the temperature change to find the heat capacity: \[ C = \frac{q}{\Delta T} \] This problem demonstrates the process of calculating thermal properties using experimental data from a calorimetric experiment.
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