3. When 0.050 mol of HCl is reactd with 0.050 mol of NaOH in 50.0 mL of water, the temperature of the water increases by 12.7"C. Given that the heat capacity of the entire system (the calorimeter and the reactant solution together) is 209.2 J/C, calculate the heat of the following reaction as written. HCI + NaOH -----> NaCl + H,O AH = kJ/mol NaOH "Cag) (ag) (ag) ().

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3. When 0.050 mol of HCl is reactd with 0.050 mol of NaOH in 50.0 mL of water, the temperature of the water
increases by 12.7"C. Given that the heat capacity of the entire system (the calorimeter and the reactant
solution together) is 209.2 J/C, calculate the heat of the following reaction as written.
HCI + NaOH
-----> NaCl + H,O
AH =
kJ/mol NaOH
"Cag)
(ag)
(ag)
().
Transcribed Image Text:3. When 0.050 mol of HCl is reactd with 0.050 mol of NaOH in 50.0 mL of water, the temperature of the water increases by 12.7"C. Given that the heat capacity of the entire system (the calorimeter and the reactant solution together) is 209.2 J/C, calculate the heat of the following reaction as written. HCI + NaOH -----> NaCl + H,O AH = kJ/mol NaOH "Cag) (ag) (ag) ().
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