4. Suppose that a student carrying a flu virus returns to an isolated campus of 1000 students. After this, the student body population doesn't change and students only interact with other students. In ten days there have been 5 cases of the flu on campus. Suppose y(t) is the number of people at the campus who have caught the flu after t days. Then 1000 – y represents the number of people who have not yet contracted the flu. Lets assume that the rate of spread of the flu is directly proportional to the total number of possible interactions between the these groups. In simple terms, increasing the number of interactions between the inflected and the non inflected causes the flu to spread quickly. A differential equation which represents this situation is given by: dy = ky(1000 – y) dt y(0) = 1, y(10) = 5

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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4. Suppose that a student carrying a flu virus returns to an isolated campus of 1000 students. After
this, the student body population doesn't change and students only interact with other students. In
ten days there have been 5 cases of the flu on campus.
Suppose y(t) is the number of people at the campus who have caught the flu after t days. Then
1000 – y represents the number of people who have not yet contracted the flu. Lets assume that
the rate of spread of the flu is directly proportional to the total number of possible interactions
between the these groups. In simple terms, increasing the number of interactions between the
inflected and the non inflected causes the flu to spread quickly. A differential equation which
represents this situation is given by:
dy
= ky(1000 – y)
dt
y(0) = 1, y(10) = 5
Find out how long it takes for 500 people to be infected with the flu.
As a side note
Trying to account for recovery is beyond this course. You can see this more interesting case in a
Differential Equations course.
this model assumes the inflected never get well and are always contagious.
Transcribed Image Text:4. Suppose that a student carrying a flu virus returns to an isolated campus of 1000 students. After this, the student body population doesn't change and students only interact with other students. In ten days there have been 5 cases of the flu on campus. Suppose y(t) is the number of people at the campus who have caught the flu after t days. Then 1000 – y represents the number of people who have not yet contracted the flu. Lets assume that the rate of spread of the flu is directly proportional to the total number of possible interactions between the these groups. In simple terms, increasing the number of interactions between the inflected and the non inflected causes the flu to spread quickly. A differential equation which represents this situation is given by: dy = ky(1000 – y) dt y(0) = 1, y(10) = 5 Find out how long it takes for 500 people to be infected with the flu. As a side note Trying to account for recovery is beyond this course. You can see this more interesting case in a Differential Equations course. this model assumes the inflected never get well and are always contagious.
Expert Solution
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Given:-

         dydt = ky1000-yy0 = 1yl0 = 5dyy1000-y = k dtdy 1y+11000-y = 1000 k dtdyy+dy1000-y = 1000 k dt

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