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4. Compute for the error due to sag. a. -0.53 m C. 0.49 m b. 4.24 m d.-0.24 m 5. What is the total correction on the tape? a -0.5214 m 0.4814 m b. -11.92 m d. -11.01 m C. 6. What is the corrected distance? b. 4583.37 m d. 4561.35 m a. 4560.44 m C. 4580.28 m

4. Compute for the error due to sag. a. -0.53 m C. 0.49 m b. 4.24 m d.-0.24 m 5. What is the total correction on the tape? a -0.5214 m 0.4814 m b. -11.92 m d. -11.01 m C. 6. What is the corrected distance? b. 4583.37 m d. 4561.35 m a. 4560.44 m C. 4580.28 m

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Answer no.4,5,6
SITUATION 1: The recorded distance is 4572.36m when the temperature is 20° and the pull was 55 N supported only at midpoint. A 200 m tape weighing 4 kg was standardized and found to be 0.02 m short at temperature of 10° and a 40 N pull when supported throughout. 1. What is the error due to tape? a. -0.02 b. 0.02 c. 0.04 d. 0.04 2. Compute for the error due to the change in temperature. (Assume a 11.6 x 10-/°C) a. 0.0116 0.0087 c. 0.0058 0.0232 3. What will be the error due to change in pull if the density of the material is 7200 kg/m and E=200 GPa? a. 0.0040 b. 0.0042 c. 0.0054 d. 0.0052 4. Compute for the error due a. -0.53 m C. 0.49 m sag. b. 4.24 m d.-0.24 m 5. What is tape? a. -0.5214 m C.0.4814 m total correction on the b. -11.92 m d. -11.01 m 6. What is the corrected distance? a. 4560.44 m C. 4580.28 m b. 4583.37 m d. 4561.35 m VIE
Transcribed Image Text:SITUATION 1: The recorded distance is 4572.36m when the temperature is 20° and the pull was 55 N supported only at midpoint. A 200 m tape weighing 4 kg was standardized and found to be 0.02 m short at temperature of 10° and a 40 N pull when supported throughout. 1. What is the error due to tape? a. -0.02 b. 0.02 c. 0.04 d. 0.04 2. Compute for the error due to the change in temperature. (Assume a 11.6 x 10-/°C) a. 0.0116 0.0087 c. 0.0058 0.0232 3. What will be the error due to change in pull if the density of the material is 7200 kg/m and E=200 GPa? a. 0.0040 b. 0.0042 c. 0.0054 d. 0.0052 4. Compute for the error due a. -0.53 m C. 0.49 m sag. b. 4.24 m d.-0.24 m 5. What is tape? a. -0.5214 m C.0.4814 m total correction on the b. -11.92 m d. -11.01 m 6. What is the corrected distance? a. 4560.44 m C. 4580.28 m b. 4583.37 m d. 4561.35 m VIE
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