4. Based on the equation below, howmany moles of aluminum sulfate(Al2(SO4)3) will be produced from thereaction of 5.8 moles of aluminumhydroxide (AI(OH)3) and excess sulfuricacid (H2SO4)?2AI(OH)3 + 3H2SO4→ Al2(SO4)3 + 6H20A. 2.9 moles of aluminum sulfateB. 3.9moles of aluminum sulfateO C. 5.8 moles of aluminum sulfateO D. 11.6 moles of aluminumsulfate

4. Based on the equation below, how many moles of aluminum sulfate (Al2(SO4)3) will be produced from the reaction of 5.8 moles of aluminum hydroxide (Al(OH)3) and excess sulfuric acid (H2SO4)? 2AI(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H20

4. Based on the equation below, how many moles of aluminum sulfate (Al2(SO4)3) will be produced from the reaction of 5.8 moles of aluminum hydroxide (Al(OH)3) and excess sulfuric acid (H2SO4)? 2AI(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H20

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

4. Based on the equation below, how
many moles of aluminum sulfate
(Al2(SO4)3) will be produced from the
reaction of 5.8 moles of aluminum
hydroxide (AI(OH)3) and excess sulfuric
acid (H2SO4)?
2AI(OH)3 + 3H2SO4
→ Al2(SO4)3 + 6H20
A. 2.9 moles of aluminum sulfate
B. 3.9moles of aluminum sulfate
O C. 5.8 moles of aluminum sulfate
O D. 11.6 moles of aluminum
sulfate

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