cn.3 4. At 25.0°C, the equilibrium constant for the reaction3 H₂(g) + N₂(g) → 2 NH3(g)is 5.9 x 106. The enthalpy of formation for NH3(g) at this temperature is -46.1 kJ/mol.Assuming that AH° and AS° does not vary with the temperature, calculate the valuesof AHO, ASO, AGO, and K for this reaction at 50.0°C. (Answer: -92.2 kJ, -180 J/K, -34kJ, 3.2 x 105)

Answered: Image /qna-images/answer/65378085-8f0b-430c-b790-80a6c80497ab.jpg

4. At 25.0°C, the equilibrium constant for the reaction 3 H₂(g) + N₂(g) → 2 NH3(g) is 5.9 x 106. The enthalpy of formation for NH3(g) at this temperature is -46.1 kJ/mol. Assuming that AHⓇ and AS° does not vary with the temperature, calculate the values of AHO, ASO, AGO, and K for this reaction at 50.0°C. (Answer: -92.2 kJ, -180 J/K, -34 kJ, 3.2 x 105)

4. At 25.0°C, the equilibrium constant for the reaction 3 H₂(g) + N₂(g) → 2 NH3(g) is 5.9 x 106. The enthalpy of formation for NH3(g) at this temperature is -46.1 kJ/mol. Assuming that AHⓇ and AS° does not vary with the temperature, calculate the values of AHO, ASO, AGO, and K for this reaction at 50.0°C. (Answer: -92.2 kJ, -180 J/K, -34 kJ, 3.2 x 105)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Balance each chemical equation Na2S (aq) + Zn(NO3)2 (aq) ----> NaNO3 (aq) + ZnS(s)
Yeast converts glucose (C6H1206) into ethanol (d = 0.789 g/mL) in a process called fermentation. An unbalanced equation for the reaction can be written as follows: CH₁206(aq) C₂H₂OH(1) + CO₂(g) - Balance this fermentation reaction by adding the missing coefficients. X X₁ He d. 1 C6H₁2O6(aq) - 2_C₂H₂OH(1)+ 2_CO₂(g) If 350.0 g of glucose yields 142.0 mL of ethanol, what is the percent yield for the reaction? % See Periodic Table See Hint
7 4. NaHSO4 (Sodium hydrogen sulfate) Number Element of atoms Na: H: S: O: Number Element of atoms Ca: P: O: X X X X Element %S = %K= X X X 5. Ca3(PO4)2 (Calcium phosphate) X X Atomic Mass X X Formula mass Atomic Mass Formula mass || || = |||||||||| = Product Product Part 2: Percent Mass Composition: The formula mass (molecular mass) and the elemental information for the compounds in Part 1. Solve for the % Mass Composition of each element in the compound. 1. K₂S (potassium sulfide).
K2SO4 (aq) + 2 H20 () 3. For which reaction will AH and AE be exactly equal to each other? 2 (g) →3 CO2 (g) + 3 H2O (g) B) 2 KOH (aq) + H2SO4 (aq) → K2SO4 (aq) + 2 H2O (1) A) C3H60 (1) +4 02 || C) N2 (g) + O2 (g) → 2 NO (2) + 02 D) 2 H2 (g) + O2 (g) →2 H20 (g) (8) E) None of the above + 02 24.02 + 4.04
A 1.473 g sample of technical grade (impure) Al2(SO4)3 was dissolved in water and treated with BaCl2 solution. When dry, the BaSO4 obtained weighed 2.942 g. What was the percent purity of the Al2(SO4)3? Al2(SO4)3 (aq) + 3 BaCl2 (aq) ----> 3 BaSO4 (s) + 2 AlCl3 (aq)
16 The odor of fish is due primarily to amines, especially methylamine (CH3NH₂). Fish is often served with a wedge of lemon, which contains citric acid. The methylamine reacts with the citric acid to form an odorless product, methylammonium citrate, thereby making less-than- fresh fish more appetizing. K₁ for CH3NH₂ = 4.407 × 10-4 CH₂NH₂ (aq) + H₂O(1)⇒ CH₂NH3(aq) + OH(aq) A. B. What is the pH of a solution that is 0.7625 M in methylamine at 25.0 °C? pH = Please provider your answer below. t Check answer → A (0) Check answer What is the pH of a solution that is 7.007×104 M in methylamine? pH = Please provider your answer below. (0
When CH₂OH is dissolved in water, how many particles are in the solution?A. 1B. 3C. 5D. 6
6. Consider the following chemical reaction: 2 Cr(OH)3(aq) >Cr₂O3(s) + 3H₂0(1) 12.00 moles of chromium (III) hydroxide is decomposed. Calculate moles of the water produced. O 18.00 moles O 1.500 moles O 4.00 moles O 12.00 moles
This equation models how pure silver (Ag) is extracted from ores of AgK(CN)2 (potassium argentocyanide), which is mined from the earth. Zinc is a reactant in the equation, and it is needed in order to extract the silver from the potassium argentocyanide ore. 2AGK(CN)2 (aq) + Zn(s) 2 Ag(s) + Zn(CN)2 (aq) + 2KCN(ag) IN GOD WE TRUST 2004 Public domain 2 How many atoms of pure zinc (Zn) are needed in the production process to create a pure silver coin of mass 24.3 grams? Answer: Zn atoms (Use 3 significant figures for answer. Format scientific notation using "e"; for example, 5.84x1016 is entered as 5.84e16)
Potassium permanganate reacts with oxalic acid (H2C2O4) in aqueous sulfuric acid according to the following reaction: 2 KMnO4(aq) + 5 H2C2O4(aq) + 3 H2SO4(aq) 2 MnSO4·H2O(s) + K2SO4(aq) + 10 CO2(g) + 6 H2O(l) The reaction is run a second time and 8.74 g of MnSO4·H2O are obtained. What volume of carbon dioxide gas is collected at 1.01 bar and 23˚C? Answer in L with the correct number of significant figures; do not use scientific notation.
This equation models how pure silver (Ag) is extracted from ores of AgK(CN)2 (potassium argentocyanide), which is mined from the earth. Zinc is a reactant in the equation, and it is needed in order to extract the silver from the potassium argentocyanide ore. 2AgK(CN)2(aq)+Zn(s)→2Ag⁡(s)+Zn(CN)2(aq)+2KCN(aq) How many atoms of pure zinc (Zn) are needed in the production process to create a pure silver coin of mass 31 grams?
Match each reaction to the sum of the coefficients of its net ionic reaction. For example, sum of coefficients of 2 H2 + O2 → 2 H2O is 2 + 1 + 2 = 5. If you are having trouble with this exercise, this 2 Fe(CIO3)3(aq) + 3 Na2CrO4(aq) → Fe2(CrO4)3(s) + 6 NaClO3(aq) 1__ Screen Reader: 2 F e(CI O3)3(aq) + 3 N a2Cr O4(a q) → F e2(Cr 04)3(s) + 6 Na Cl O3(aq) Pb(ClO3)4(aq) + 4 NaCl(aq) → PbC14(s) + 4 NaCIO3(aq) 2 - Screen Reader: Pb(Cl 03)4(a q)+ 4 N a Cl(aq) → PbC14(s) + 4 N a Cl 03(aq) SnC14(aq) + 2 Na2O(aq) → SnO2(s) + 4 NaCl(aq) A Screen Reader: SnC14(a q) + 2 N a2O(a q) → Sn O2(s) + 4 Na Cl(aq) Fe(CIO3)2(aq) + Na2CrO4(aq) → FeCrO4(s) + 2 NaClO3(aq) 3 Screen Reader: Fe(CI O3)2(a q) + N a2Cr O4(a q) → F e Cr 04 (s) + 2 Na Cl O3(a a) 4 1.3 2.4 3.6 4.8