4. A student is given the task of determining the I content of tablets that contain KI and an inert, water-soluble sugar as a filler. A tablet is dissolved in 50.0 mL of distilled water, and an excess of 0.20 M Pb(NO3)2(ag) is added to the solution. A yellow precipitate forms, which is then filtered, washed, and dried. The data from the experiment are shown in the table below. Mass of KI tablet 0.425 g 1.462 g Mass of thoroughly dried filter paper Mass of filter paper + precipitate after first drying 1.775 g 1.699 g Mass of filter paper + precipitate after second drying Mass of filter paper + precipitate after third drying 1.698 g (a) Write the balanced chemical reaction that occurs above when the precipitate forms, (b) Explain the purpose of drying and weighing the filter paper with the precipitate three times. (c) Calculate the number of moles of precipitate that is produced in the experiment.

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### Determining the Content of \( I^- \) in Tablets

#### Experiment Overview
A student is tasked with determining the \( I^- \) (iodide ion) content in tablets that contain KI and an inert, water-soluble sugar as a filler. The experiment involves dissolving a tablet in 50.0 mL of distilled water and adding an excess of 0.20 M \( Pb(NO_3)_2(aq) \) to the solution. A yellow precipitate forms, which is then filtered, washed, and dried. The data collected from the experiment is shown in the table below:

| Measurement Description                                | Mass (g) |
|--------------------------------------------------------|----------|
| Mass of KI tablet                                      | 0.425 g  |
| Mass of thoroughly dried filter paper                  | 1.462 g  |
| Mass of filter paper + precipitate after first drying  | 1.775 g  |
| Mass of filter paper + precipitate after second drying | 1.699 g  |
| Mass of filter paper + precipitate after third drying  | 1.698 g  |

#### Questions and Calculations

**(a) Write the balanced chemical reaction that occurs when the precipitate forms.**

The balanced chemical reaction for the formation of the precipitate is:

\[ 2KI + Pb(NO_3)_2 \rightarrow 2KNO_3 + PbI_2 \]

In this reaction, potassium iodide (\( KI \)) reacts with lead nitrate (\( Pb(NO_3)_2 \)) to form potassium nitrate (\( KNO_3 \)) and lead(II) iodide (\( PbI_2 \)), the yellow precipitate.

**(b) Explain the purpose of drying and weighing the filter paper with the precipitate three times.**

Drying and weighing the filter paper with the precipitate three times ensures that all water has been removed from the precipitate, providing a consistent and accurate final mass. By recording mass after each drying cycle, we make sure that:

- All moisture is evaporated
- Any changes in mass are accounted for until a constant mass is reached, indicating that drying is complete.

**(c) Calculate the number of moles of precipitate that is produced in the experiment.**

To calculate the number of moles of precipitate (\( PbI_2 \)) produced, we first determine the mass of the dry precipitate:

Final
Transcribed Image Text:### Determining the Content of \( I^- \) in Tablets #### Experiment Overview A student is tasked with determining the \( I^- \) (iodide ion) content in tablets that contain KI and an inert, water-soluble sugar as a filler. The experiment involves dissolving a tablet in 50.0 mL of distilled water and adding an excess of 0.20 M \( Pb(NO_3)_2(aq) \) to the solution. A yellow precipitate forms, which is then filtered, washed, and dried. The data collected from the experiment is shown in the table below: | Measurement Description | Mass (g) | |--------------------------------------------------------|----------| | Mass of KI tablet | 0.425 g | | Mass of thoroughly dried filter paper | 1.462 g | | Mass of filter paper + precipitate after first drying | 1.775 g | | Mass of filter paper + precipitate after second drying | 1.699 g | | Mass of filter paper + precipitate after third drying | 1.698 g | #### Questions and Calculations **(a) Write the balanced chemical reaction that occurs when the precipitate forms.** The balanced chemical reaction for the formation of the precipitate is: \[ 2KI + Pb(NO_3)_2 \rightarrow 2KNO_3 + PbI_2 \] In this reaction, potassium iodide (\( KI \)) reacts with lead nitrate (\( Pb(NO_3)_2 \)) to form potassium nitrate (\( KNO_3 \)) and lead(II) iodide (\( PbI_2 \)), the yellow precipitate. **(b) Explain the purpose of drying and weighing the filter paper with the precipitate three times.** Drying and weighing the filter paper with the precipitate three times ensures that all water has been removed from the precipitate, providing a consistent and accurate final mass. By recording mass after each drying cycle, we make sure that: - All moisture is evaporated - Any changes in mass are accounted for until a constant mass is reached, indicating that drying is complete. **(c) Calculate the number of moles of precipitate that is produced in the experiment.** To calculate the number of moles of precipitate (\( PbI_2 \)) produced, we first determine the mass of the dry precipitate: Final
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