A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further precipitation occurs. TH precipitate is collected by filtration, dried, and weighed. A total of 12.18 g PbCl,(s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO,),(aq) solution. concentration: M
A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further precipitation occurs. TH precipitate is collected by filtration, dried, and weighed. A total of 12.18 g PbCl,(s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO,),(aq) solution. concentration: M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO₃)₂(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 12.18 g PbCl₂(s) is obtained from 200.0 mL of the original solution.
Calculate the molarity of the Pb(NO₃)₂(aq) solution.
**Concentration:** [_____] M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3cee4417-a7cf-430c-b77c-2ef456656a7a%2F7eaa024e-e2af-496d-bdf5-d8d84daa312a%2Fqmix6fe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO₃)₂(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 12.18 g PbCl₂(s) is obtained from 200.0 mL of the original solution.
Calculate the molarity of the Pb(NO₃)₂(aq) solution.
**Concentration:** [_____] M
Expert Solution
Step 1
Given mass of lead (II) chloride =12.18 g
Molar mass of lead (II) chloride = 278.1 g/mol
Number of moles of lead (II) chloride = 12.18/278.1 = 0.0438 mol
Step 2
The balanced chemical equation for the reaction of sodium chloride and lead (II) nitrate can be written as follows:
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