4.A sample survey was conducted to estimate the population proportion p that has a certaincharacteristic. Stratified simple random sampling was used. The results are given below.StratumStratum SizeSample SizePi1100500.80260200.703150750.60480200.50a)b)Find an estimate and a 95% confidence interval for the population proportion p andinterpret the meaning of the confidence interval.For a future survey, stratum sample sizes are to be recalulated to estimate p to within0.1 using an appropriate allocation method. What allocation method would you use if unitcosts are given as c₁ = 4, c₂ = 2, c₁ = 5, c = 1? Why? Calculate the stratum samplesizes using the allocation you have chosen.

References Mertler, C. A., Vannatta, R. A., & LaVenia, K. N. (2021). Advanced and multivariate…

Answered: 4. A sample survey was conducted to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The current speed limit is 60 mph. This sample of speeds was taken at 4pm on a Monday. Use the data to construct a 80% confidence interval estimate of the standard deviation for the population speeds. 60 62 62 65 56 62 54 61 60 61 69 58 66 what is the lower limit what is the upper limit
Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4321patients treated with the drug, 148 developed the adverse reaction of nausea. Construct a 95% confidence interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion p. ______________ (Round to three decimal) b. identify the value of the margin of error E E=______________ c. construct the confidence interval _____<p<________ d. write a statement that correctly interprets the confidence interval.
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Assuming that the population is normally distributed, construct a 95% confidence interval for the population mean for each of the samples below. Explain why these two samples produce different confidence intervals even though they have the same mean and range. Sample A: 1 2 4 4 5 5 7 8 Full data set Sample B: 1 2 3 4 5 6 7 8 Question content area bottom Part 1 Construct a 95% confidence interval for the population mean for sample A. enter your response here≤μ≤enter your response here
A sample mean, sample size, population standard deviation, and confidence level are provided. Use this information to complete parts (a) through (c) below. x=35, n=27, σ=5 confidence level=90% a. Use the one-mean z-interval procedure to find a confidence interval for the mean of the population from which the sample was drawn. The confidence interval is from _______ to _________. (Type integers or decimals rounded to one decimal place as needed.) b. Obtain the margin of error by taking half the length of the confidence interval. What is the length of the confidence interval? ____________ (Type an integer or decimal rounded to one decimal place as needed.) c. Obtain the margin of error by using the formula E=zα2•σn. Identify the critical value. zα2=____________ (Type an integer or decimal rounded to two decimal places as needed.) What is the margin of error obtained using the methods of parts (b) and(c)? _________ (Type an integer or decimal…
K Large samples of women and men are obtained, and the hemoglobin level is measured in each subject. Here is the 95% confidence interval for the difference between the two population means, where the measures from women correspond to population 1 and the measures from men correspond to population 2: -1.76 g/dL
Use the sample information. X = 40, 0 = 4, and n= 20 to calculate the following confidence intervals assuming the sample is from a normal population. A. 90% confidence from____to____ (Round 4 decimal places.) B. 95% confidence interval is from_____to_____ (Round 4 decimal places.) C. 99% confidence interval is from______to_____ (Round 4 decimal places.) D. Describe how the intervals change as you increase the confidence level. A. The interval gets narrower as the confidence level increases B. The interval gets wider as a confidence level decreases C. The interval gets wider as a confidence level increases D. The interval stays the same as the confidence level increases
A random sample of statistics students were asked to estimate the total number of hours they spend watching television in an average week. The responses are recorded in Table. Use this sample data to construct a 98% confidence interval for the mean number of hours statistics students will spend watching television in one week. Assume the population is normally distributed. (Give your answer to 3 decimal places if necessary.) 20 13 1 10 20 0 10 13 16 10 1 17 18 3 9 (?,?)
Determine whether the following statements are True or False: If we increase the confidence level C, then the width of the CI decreases, i.e., the CI becomes narrower. (Hint: think about what happens to the margin of error m) Suppose the mean of a population µ = 100. If we found that the margin of error is m = 2 for level of confidence 98%, then we can be 98% confident that a sample mean (computed from a sample of the same size used to compute m) is in the interval (98, 102).
Use the given confidence interval to find the margin of error and the sample proportion. (0.596,0.626) E= (Type an integer or a decimal.) p%3D(Type an integer or a decimal.) Type here to search
A random sample of n = 9 values taken from a normally distributed population with a population variance of 25 resulted in the sample values shown below. Use the sample values to construct a 90% confidence interval estimate for the population mean. 46 61 50 54 47 54 44 44 52 The 90% confidence interval is (Round to two decimal places as needed. Use ascending order.)

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