KIf a sample proportion is 0.56, which of the following could be a 90% confidence interval for the population proportion?Select all that apply.A. Lower bound: 0.53, Upper bound: 0.61B. Lower bound: 0.48; Upper bound: 0.64C. Lower bound: 0.40; Upper bound: 0.64D. Lower bound: 0.64; Upper bound: 0.80E. Lower bound: 0.52; Upper bound: 0.60

The problem is asking us to determine which of the given intervals could be a 90% confidence…

Answered: K If a sample proportion is 0.56, which…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For the sample data set: (0,0) (2,3) (3,3) (6,4) (9,8) a. Give a point estimate for the mean value y in the sub-population determined by the condition X=4 b. Construct the 90% confidence interval for that mean value
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Construct a 99% confidence interval for the population mean, based on the following sample data: 16.3, 15,9, 15.4, 16.7, and 16.9. Assume sampling from a normal population. Somple meen 1 16.3+ 15. 13+ 15.4 +16.7+16. = 0.49 2 5 16.04 5 Standard deviation. (16.3 - 16.04)² = 0.0672 (15.9-16.04)² 8 0186 ? 31-672 0.4356 (15.4-16.041 20.4086 2 (16.7-16-04)² = 116.8-16.0412 = 0.7396 82 1.1677 20.646
4. The following sample of numbers is chosen from a normally distributed population. 22, 25, 28, 30, 27 The 95% confidence interval for the population mean is (A) 26.4 + 1.0033 (B) 26.4 ± 1.3638 (C) 26.4 + 2.2435 (D) 26.4 + 2.6731 (E) 26.4 + 3.7860
10 squirrels were found to have an average weight of 610 grams with a sample standard deviation of 7.75 . Find the 95 % confidence interval of the true mean weight (assume the t-student distribution). A.)(608.25, 614.16) B.)(561.02, 614.16) C.) (604.46,615.54) D.) (513.79, 612.77)
3. Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11,12, 15. There are 10,000 total students. Average GPA: Unknown, StandardDeviation of GPA: 0.02 and it’s Normal.a. Find the mean and standard deviation for GPA.b. Calculate a 95% confidence interval for the populations mean GPA.c. Use Correlation formula to find r between GPA and Age.d. Find Regression Line Equation.e. If a student’s age is 13, what is the corresponding GPA?
A simple random sample of 5 observations from a normal distribution was taken, and the following values were obtained: {15, 19, 19, 20, 22}. A 95% confidence interval for the mean is O A. (16.569, 21.431) O B. (15.835, 22.165) O C.(16.069, 21.931) O D. (17.124, 20.876) O E. (16.765, 21.235)
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 28.9 14.3 34.2 35.2 42.7 41.3 39.7 44.2 26.8 36.2 20.4 34.6 Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population.
The following sample data are from a normal population: 10, 8,12,15, 13, 11, 6, 5 a. What is the point estimate of the population mean? b. What is the point estimate of the population standard deviation (to 3 decimals)? c. with 95% confidence, what is the margin of error for the estimation of the population mean (to 1 decimal)? d. What is the 95% confidence interval for the population mean (to 1 decimal)? ,
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Next question If a sample proportion is 0.68, which of the following could be a 90% confidence interval for the population proportion? ..... Select all that apply. A. Lower bound: 0.59; Upper bound: 0.77 B. Lower bound: 0.66; Upper bound: 0.70 OC. Lower bound: 0.50; Upper bound: 0.77 D. Lower bound: 0.77; Upper bound: 0.95 E. Lower bound: 0.67; Upper bound: 0.71 F3 F4 F5 F7 F8 24 4. %23 2 3. 6. Left control option command
Find 90% confidence interval

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