A roller-coaster car with a mass ofmcar = 200 kg200.0kg (including the riders) is moving4.00 mAto the right at a speed of 4.00m/s atpoint A in the diagram. This point is15.0 m15.0m above the ground. Determine the6.0 mspeed at point B if all forms of resistiveforces are ignored. If the speed of theroller-coaster at point B is actually approximately 12.6m/s, what is the workdone by all resistive forces?Answer: Without resistive forces, the speed of the roller-coaster at Point B willbe approximately 13.3m/s. Given the actual speed, the work done byall the resistive forces will be 3.40x10 J.Source: modified from Nelson, Physics 12, 2002, pp.219-220, Sample Problem

Given, mcar=200 kgvA=4.00 m/shA=15.0 mhB=6.0m

Answered: 4. A roller-coaster car with a mass of…

Similar questions

10. A stationary block is released on a frictionless ramp at a height of 3.0 m. There are other hill heights along the ramp as shown in the figure. The hills have identical circular tops, and the block does not fly off any hill. If the mass of the block is 4 Kg, what would be the velocity as it passes hill (1)?
A 4.00kg block moves with an initial speed of3.50 km/h downhillover an inclined plane as shown in the figure. The height of the inclined plane is 51.3cm and the friction coefficient between the block and the incline is 0.120. a.How much is the speed of the block at the midpoint of the inclined side. b.How much is the speed of the block at the bottom of the inclined side.
10. Block 1 with a mass of 1.0 kg slides down a frictionless ramp with a height of 3.0 m and cllides with block 2 which has a mass of 2.0 kg. The flat surface has friction with a friction coefficient of 0.50. 2 a. Determine the speed of block 1 when it reaches the bottom of the ramp.
A 9.0-kg bunny slides from rest down a frictionless incline from a height of 5.0 m. A constant frictional force, introduced at point A, brings the bunny to rest at point B, 19 m to the right of point A. What is the Speed of the bunny before it reaches point A? What is the coefficient of kinetic friction, µk, of the surface from A to B?
5. A top WNBA player can jump about .7 meters off the ground. If her mass is 50 kg, what force must she exert against the ground? Assume she crouches a distance of .2 metes prior to jumping, and thus the upward force has this distance to act before leaving the ground. 6. A block is given an initial speed of 4 meters per second up the 0 = 22° plane shown below. Ignoring friction, %3D (a) how far up the plane will it go? (b) How much time elapses before it returns to its starting point? R 4m/s s 22°
6. Two packages that start sliding down a 20° ramp from rest a distance d = 4.30 m. For package A: Ma = 5.00 kg and ukA = 0.30. %3D For package B: mB = 7.00 kg and ukB = 0.20. Find the speed of both packages when they reach the bottom. 20°
A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The friction force on the box is 75.0 N. The cabinet starts from rest. What is its speed at the end of the ramp, in m/s? Use g = 10.0 m/s2.
At the Earth's surface, a projectile is launched straight up at a speed of 7.5 km/s. To what height will it rise? Ignore air resistance. 8.12e+06 X Your response differs from the correct answer by more than 10%. Double check your calculations. m
A ball of mass m is released from the top of a frictionless inclined plane AB with an initial velocity v₁ = 2m/s from a height h₁ = 5 m above the ground. It slides along the inclined plane and reaches the bottom at point B of height h = 2 m above the ground with a velocity v that will be equal to: Take g = 10 m/s². v₁=2m/s A₁ Vf=? hi h=0 O 6.63 m/s 8 m/s O 4 m/s O 12.8 m/s O 17.32 m/s B hf
If the velocity of a horizontally moving body is doubled its gravitational potential energy... Please explain MCQ choice (with calculations where needed) in the Rationale section! A. gets doubled B. does not change C. becomes half D. becomes 4 times bigger
B9
an object is acted by a frictional force. the work done by this frictional force is a. negative because friction force is opposite its motion b. zero because fk = ukn and normal force is perpendicular to the motion c. zero because friction is not the cause of its motion d. could be positive, negative or zero because the direction of friction is unknown