**Problem Statement:**A 93-kg firefighter slides down a fire pole starting from rest. The average frictional force exerted on him by the pole has a magnitude of 840 N. By the time he reaches the bottom of the pole, his speed is 3.6 m/s. Determine the distance he slid down the pole.**Diagram Explanation:**- The diagram shows the firefighter at the top and bottom of the pole.- At the top, he is positioned before beginning his slide, marked by height \( h_0 \).- At the bottom, his speed is labeled as \( v_f = 3.6 \, \text{m/s} \).**Variables:**- Mass of the firefighter: 93 kg- Frictional force: 840 N- Final speed: 3.6 m/s- Initial speed: 0 m/s (rest position)- Height/sliding distance: \( h_0 \) (to be determined)This problem involves concepts of energy transformations and dynamics, specifically considering gravitational potential energy, kinetic energy, and work done against friction.

We will first find the acceleration of the firefighter using Newton's second law. We then use…

Answered: Starting from rest, a 93-kg firefighter…

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Starting from rest, a 93-kg firefighter slides down a fire pole. The average frictional force exerted on him by the pole has a magnitude of 840 N, and his speed at the bottom of the pole is 3.6 m/s. How far did he slide down the pole? ho