4. A random sample of 25 employees for the retailer showed a samplemean of 9.2 minutes and a standard deviation of 2 minutes. Assume thatthe time spent by employees on personal phone calls is normallydistributed. Let u denote the mean time spent by employees spent onpersonal phone calls.(a) Find the 95% confidence interval for u.(b) An employee group for a national retailer claims that the mean timespent by employees on personal phone calls is less than 10 minutesper day. Specify the correct null and alternative hypotheses you woulduse to investigate the employee group's claim.(c) Find the value of the standardized test statistic.(d) Find the rejection region at a = .05 and state your conclusion in thecontext of the problem.

From given data we have : x¯=9.2,s=2n=25

Answered: 4. A random sample of 25 employees for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard deviation of 3 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit? Question Help v (a) The percent of customers that receive the service for half-price is %. (Round to two decimal places as needed.) (b) The guaranteed time limit is minutes. (Round up to the nearest integer as needed.) Enter your answer in each of the answer boxes. 1:20 PM P Type here to search AD4 d0E ENG 3/21/2021 DELL PgUp Delete PrtScr Insert F11 F12 F10 F9 F7 F8 F6 F4 F5 F2 F3 A Backspace Esc F1 &…
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard deviation of 2.5 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want to give the discount to more than 4% of its customers, how long should it make the guaranteed time limit? Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2).
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