The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 17 minutes and a standard deviation of 4 minutes. (a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? (b) If the automotive center does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit? Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) The percent of customers that receive the service for half-price is%. (Round to two decimal places as needed.) minutes. (b) The guaranteed time limit is (Round up to the nearest minute.)

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# Standard Normal Distribution Table

The standard normal distribution table is a mathematical table commonly used to find the probability that a statistic is observed below, above, or between values on the standard normal distribution, which is a normal distribution with a mean of 0 and a standard deviation of 1. The table is important when performing statistical hypothesis testing.

## Diagrams

Each page of the table displays a bell curve (normal distribution curve) graphically representing how the values in the table are distributed. The area under the curve to the left of a given z-score represents the cumulative probability of obtaining that score or less.

### Page 1

#### z-scores ranging from -3.4 to -0.1

Each cell within the table shows the probability (area under the curve) associated with the corresponding z-score, which is a measure of how many standard deviations an element is from the mean.

- **Vertical Column**: Represents the z-scores in increments of 0.1, starting from -3.4 to -0.1.
- **Horizontal Row**: The top row shows increments of 0.01, adding this to the z-score from the vertical column.
  
For example, to find the cumulative probability for a z-score of -1.23, you would find -1.2 in the column and move across to the 0.03 column to get 0.1093.

### Page 2

#### z-scores ranging from 0.0 to 3.4

- **Vertical Column**: Represents z-scores in increments of 0.1, starting from 0.0 to 3.4.
- **Horizontal Row**: Similar to page 1, the top row indicates increments of 0.01.
  
For instance, a z-score of 0.57 would be found by locating 0.5 in the vertical column and moving to the 0.07 column, resulting in a cumulative probability of 0.7157.

### Usage

These tables are essential in determining probabilities for normally distributed data, making them indispensable for statistical analysis, hypothesis testing, and various fields that require probabilistic evaluation.
Transcribed Image Text:# Standard Normal Distribution Table The standard normal distribution table is a mathematical table commonly used to find the probability that a statistic is observed below, above, or between values on the standard normal distribution, which is a normal distribution with a mean of 0 and a standard deviation of 1. The table is important when performing statistical hypothesis testing. ## Diagrams Each page of the table displays a bell curve (normal distribution curve) graphically representing how the values in the table are distributed. The area under the curve to the left of a given z-score represents the cumulative probability of obtaining that score or less. ### Page 1 #### z-scores ranging from -3.4 to -0.1 Each cell within the table shows the probability (area under the curve) associated with the corresponding z-score, which is a measure of how many standard deviations an element is from the mean. - **Vertical Column**: Represents the z-scores in increments of 0.1, starting from -3.4 to -0.1. - **Horizontal Row**: The top row shows increments of 0.01, adding this to the z-score from the vertical column. For example, to find the cumulative probability for a z-score of -1.23, you would find -1.2 in the column and move across to the 0.03 column to get 0.1093. ### Page 2 #### z-scores ranging from 0.0 to 3.4 - **Vertical Column**: Represents z-scores in increments of 0.1, starting from 0.0 to 3.4. - **Horizontal Row**: Similar to page 1, the top row indicates increments of 0.01. For instance, a z-score of 0.57 would be found by locating 0.5 in the vertical column and moving to the 0.07 column, resulting in a cumulative probability of 0.7157. ### Usage These tables are essential in determining probabilities for normally distributed data, making them indispensable for statistical analysis, hypothesis testing, and various fields that require probabilistic evaluation.
**Automotive Service Time Analysis**

The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 17 minutes and a standard deviation of 4 minutes.

### Tasks

**(a)** The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? 

- **Answer**: The percent of customers that receive the service for half-price is [ ]%.  
  (Round to two decimal places as needed.)

**(b)** If the automotive center does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit?

- **Answer**: The guaranteed time limit is [ ] minutes.  
  (Round up to the nearest minute.)

### Additional Resources

- Click here to view the standard normal distribution table (page 1).
- Click here to view the standard normal distribution table (page 2). 

The tables provided are necessary for determining the exact percentages and time limits, utilizing the properties of the normal distribution curve. The analysis involves calculating the area under the normal distribution curve for specific conditions outlined in the tasks.
Transcribed Image Text:**Automotive Service Time Analysis** The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 17 minutes and a standard deviation of 4 minutes. ### Tasks **(a)** The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service for half-price. What percent of customers receive the service for half-price? - **Answer**: The percent of customers that receive the service for half-price is [ ]%. (Round to two decimal places as needed.) **(b)** If the automotive center does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit? - **Answer**: The guaranteed time limit is [ ] minutes. (Round up to the nearest minute.) ### Additional Resources - Click here to view the standard normal distribution table (page 1). - Click here to view the standard normal distribution table (page 2). The tables provided are necessary for determining the exact percentages and time limits, utilizing the properties of the normal distribution curve. The analysis involves calculating the area under the normal distribution curve for specific conditions outlined in the tasks.
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