4. (a) If w is humidity ration, o is relative humidity, Pw is partial pressure of water vapor in the air, Tis air temperature, and Pis the total pressure of 0.62198PW/(P- Pw). (b) If P=101.3kPa, o = 50%, w = 0.014 kg/kg dry air, find Pw, T, and Psat. (c) If P=101.3kPa, w = 0.008 kg/kg dry air, T= 25 °C, find p. (d) In problem (c), if Tincreases from 25 to 35 °C, find p. the air, derive that w = %3D

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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D4
4. (a) If w is humidity ration, o is relative humidity, Pw is partial pressure of
water vapor in the air, Tis air temperature, and Pis the total pressure of
the air, derive that w = 0.62198PW/(P- Pw).
(b) If P=101.3kPa, o = 50%, w = 0.014 kg/kg dry air, find Pw, T, and Psat.
(c) If P=101.3kPa, w = 0.008 kg/kg dry air, T= 25 °C, find p.
(d) In problem (c), if Tincreases from 25 to 35 °C, find p.
!3!
Transcribed Image Text:4. (a) If w is humidity ration, o is relative humidity, Pw is partial pressure of water vapor in the air, Tis air temperature, and Pis the total pressure of the air, derive that w = 0.62198PW/(P- Pw). (b) If P=101.3kPa, o = 50%, w = 0.014 kg/kg dry air, find Pw, T, and Psat. (c) If P=101.3kPa, w = 0.008 kg/kg dry air, T= 25 °C, find p. (d) In problem (c), if Tincreases from 25 to 35 °C, find p. !3!
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