4. A 3-phase ring distributor ABCD fed at A at 11 kV supplies balanced loads of 40 A at 0-8 p.f. lagging at B, 50 A at 0-707 p.f. lagging at C and 30 A at 0-8 p.f. lagging at D, the load currents being referred to the supply voltage at A. The impedances per phase of the various sections are : Section AB = (1 + j 2) N Section CD = (1 + j l)Q Calculate the currents in various sections and station bus-bar voltages at B, C and D. Section BC = (2 +j 3)L Section DA = (3 + j 4)N [Current in AB = (53-8 -j 46) amp ; BC = (21-8 – j 22) amp. CD = (-13-55 +j 13-35) amp ; DA = (-40-55 -j 26-45) amp. V = (6212-5 -j 61-6) volts/phase; Ve = (6103-j 83) volts/phase Vp (6129-8-j 82-8) volts/phase] %3D
Short Transmission Line
A short transmission line is a transmission line that has a length less than 80 kilometers, an operating voltage level of less than 20 kV, and zero capacitance effect.
Power Flow Analysis
Power flow analysis is a topic in power engineering. It is the flow of electric power in a system. The power flow analysis is preliminary used for the various components of Alternating Current (AC) power, such as the voltage, current, real power, reactive power, and voltage angles under given load conditions and is often known as a load flow study or load flow analysis.
Complex Form
A power system is defined as the connection or network of the various components that convert the non-electrical energy into the electric form and supply the electric form of energy from the source to the load. The power system is an important parameter in power engineering and the electrical engineering profession. The powers in the power system are primarily categorized into two types- active power and reactive power.
![4. A 3-phase ring distributor ABCD fed at A at 11 kV supplies balanced loads of 40 A at 0-8 p.f. lagging at
B, 50 A at 0-707 p.f. lagging at C and 30 A at 0-8 p.f. lagging at D, the load currents being referred to the
supply voltage at A.
The impedances per phase of the various sections are :
Section AB = (1 + j 2)N
Section CD = (1 + j l) Q
Calculate the currents in various sections and station bus-bar voltages at B, C and D.
Section BC = (2 + j 3) Q
Section DA = (3 + j 4) Q
[Current in AB = (53-8– j 46) amp ; BC = (21-8– j 22) amp.
CD = (-13-55 + j 13-35) amp ; DA = (-40-55 - j 26-45) amp.
V = (6212-5 -j 61-6) volts/phase ; Ve= (6103 – j 83) volts/phase
Vp = (6129-8 – j 82-8) volts/phase]
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