Calculate all phase and line currents and all phase and line voltages, if Zp is equal to (115.0 -/63.0) 9. The phase voltage Van is The phase voltage Vbn is The phase voltage Vcn is The line voltage Vab is The line voltage Vbcis The line voltage Vca is The line current laA is The line current log is The line current lccis L 2 2 °V. °V. ° V. V. °V. °V. A. (Round the final answers to four decimal places.) A. (Round the final answers to four decimal places.) A. (Round the final answers to four decimal places.)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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### Electrical Engineering Problem Set

**Assumptions:**
- The system is balanced.
- \(R_w = 0\).
- \(V_{an} = 208 \angle 0^\circ \text{ V}\).
- A positive phase sequence applies.

**Instructions:**
Report your answers with positive magnitudes, and all angles should be in the range from -360 to +360 degrees.

---

### Task:
Calculate all phase and line currents as well as phase and line voltages, given that \(Z_p\) is equal to \(115.0 - j63.0 \, \Omega\).

**Required Calculations:**

1. The phase voltage \(V_{an}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\).

2. The phase voltage \(V_{bn}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\).

3. The phase voltage \(V_{cn}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\).

4. The line voltage \(V_{ab}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\).

5. The line voltage \(V_{bc}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\).

6. The line voltage \(V_{ca}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\).

7. The line current \(I_{aA}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ A}\).
   - *Round the final answer to four decimal places.*

8. The line current \(I_{bB}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ A}\).
   - *Round the final answer to four decimal places.*

9. The line current \(I_{cC}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ A}\).
   - *Round the final answer to four decimal places.*

---

End of problem set.
Transcribed Image Text:### Electrical Engineering Problem Set **Assumptions:** - The system is balanced. - \(R_w = 0\). - \(V_{an} = 208 \angle 0^\circ \text{ V}\). - A positive phase sequence applies. **Instructions:** Report your answers with positive magnitudes, and all angles should be in the range from -360 to +360 degrees. --- ### Task: Calculate all phase and line currents as well as phase and line voltages, given that \(Z_p\) is equal to \(115.0 - j63.0 \, \Omega\). **Required Calculations:** 1. The phase voltage \(V_{an}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\). 2. The phase voltage \(V_{bn}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\). 3. The phase voltage \(V_{cn}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\). 4. The line voltage \(V_{ab}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\). 5. The line voltage \(V_{bc}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\). 6. The line voltage \(V_{ca}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ V}\). 7. The line current \(I_{aA}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ A}\). - *Round the final answer to four decimal places.* 8. The line current \(I_{bB}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ A}\). - *Round the final answer to four decimal places.* 9. The line current \(I_{cC}\) is \(\_\_\_\_\_ \angle \_\_\_\_\_^\circ \text{ A}\). - *Round the final answer to four decimal places.* --- End of problem set.
**Educational Content on Three-Phase Circuit Analysis**

---

**Introduction:**

Welcome to this educational module on the analysis of balanced three-phase circuits. Understanding such systems is crucial for grasping the fundamentals of electrical engineering, particularly in power distribution.

---

**Problem Statement:**

**Required Information:**

Consider the given circuit diagram. In this balanced three-phase system:

- \( R_w = 0 \)
- The line-to-neutral voltage \( V_{an} \) is given as \( 208 \angle 0^\circ \) volts
- A positive phase sequence applies

Your task is to calculate all phase and line currents, as well as all phase and line voltages, given that \( Z_p \) equals \( (115.0 - j63.0) \, \Omega \).

**Instructions:**

Report your answers ensuring that:

- All magnitudes are positive
- All angles are within the range of negative 360 degrees to positive 360 degrees

---

**Circuit Explanation:**

The circuit diagram features:

- Three-phase voltage sources labeled \( V_{cn}, V_{bn}, \) and \( V_{an} \), connected in a wye (Y) configuration.
- Each phase is connected through line impedances \( R_w \), assumed to be zero in this scenario, indicating negligible line resistance.
- Load impedances \( Z_p \) are connected in parallel across each phase and are characterized by both resistive and reactive components.

**Objective:**

The goal is to systematically determine the electrical parameters of the circuit under balanced conditions. This entails using complex power formulas and phasor mathematics to derive current and voltage across different parts of the circuit.

**Example Calculation Approach:**

1. **Calculate line current \( I_a \):**

   Using Ohm's Law for AC circuits: 
   
   \[
   I_a = \frac{V_{an}}{Z_p}
   \]
   
   Substituting the given values, perform the complex division to determine \( I_a \).

2. **Determine phase and line voltages:**

   Use the relationships inherent in balanced systems and phasor transformations:
   
   - Line-to-line voltage: \( V_{ab} = V_{an} \sqrt{3} \angle (30^\circ) \)
   - Verify equality in magnitudes due to balance.

3. **Checking phase currents:**

   Equally measure \( I_b \) and \( I
Transcribed Image Text:**Educational Content on Three-Phase Circuit Analysis** --- **Introduction:** Welcome to this educational module on the analysis of balanced three-phase circuits. Understanding such systems is crucial for grasping the fundamentals of electrical engineering, particularly in power distribution. --- **Problem Statement:** **Required Information:** Consider the given circuit diagram. In this balanced three-phase system: - \( R_w = 0 \) - The line-to-neutral voltage \( V_{an} \) is given as \( 208 \angle 0^\circ \) volts - A positive phase sequence applies Your task is to calculate all phase and line currents, as well as all phase and line voltages, given that \( Z_p \) equals \( (115.0 - j63.0) \, \Omega \). **Instructions:** Report your answers ensuring that: - All magnitudes are positive - All angles are within the range of negative 360 degrees to positive 360 degrees --- **Circuit Explanation:** The circuit diagram features: - Three-phase voltage sources labeled \( V_{cn}, V_{bn}, \) and \( V_{an} \), connected in a wye (Y) configuration. - Each phase is connected through line impedances \( R_w \), assumed to be zero in this scenario, indicating negligible line resistance. - Load impedances \( Z_p \) are connected in parallel across each phase and are characterized by both resistive and reactive components. **Objective:** The goal is to systematically determine the electrical parameters of the circuit under balanced conditions. This entails using complex power formulas and phasor mathematics to derive current and voltage across different parts of the circuit. **Example Calculation Approach:** 1. **Calculate line current \( I_a \):** Using Ohm's Law for AC circuits: \[ I_a = \frac{V_{an}}{Z_p} \] Substituting the given values, perform the complex division to determine \( I_a \). 2. **Determine phase and line voltages:** Use the relationships inherent in balanced systems and phasor transformations: - Line-to-line voltage: \( V_{ab} = V_{an} \sqrt{3} \angle (30^\circ) \) - Verify equality in magnitudes due to balance. 3. **Checking phase currents:** Equally measure \( I_b \) and \( I
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