4) Use data for AG°f to calculate equilibrium constants for each reaction at 25C:a) C(s - graphite)C (s-diamond)Jb) 4 Ag + O₂ = 2 Ag₂OR=631Mal R SrF2(s)Sro(s)SrS04(s)Ti(g)At 298K and 1 atm(CH3)2CO(1)C(s, diamond)C(s, graphite)C10H8(s) naphthaleneC12H26(1)C2H2(g)C2H4(g)C2H5OH(1)C2H6(g)C2N2(g)3H603(s) (lactic acid)3H8(g)H10(g)H12(1) cyclohexaneH1206/c)-1216.3-592.0-1445473OAHf (kJ/mol)-247.61.9075.3-350.9227.452.4-277.6-84.0308.9-694.1-103.8-125.7-156.2-562.4-1334428.40AGf (kJ/mol)-155.72.9020128.1209.968.4-174.8-32.0297.282.155.5122180.330.6-522.9-23.4-17.1526.7S (J/mol K)200.42.385.74166.9490.6200.9219.3160.7229.2242.3142.3270.3310.1204.3

Answered: Image /qna-images/answer/fbfed2ca-6a83-44a8-9a8a-6813b3b856c6.jpg

Answered: 4) Use data for AG°f to calculate…

4) Use data for AG°f to calculate equilibrium constants for each reaction at 25C: J ·R = (31 Mal R a) C(s-graphite) = C (s-diamond) b) 4 Ag + O₂ = 2 Ag₂O

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

4) Use data for AG°f to calculate equilibrium constants for each reaction at 25C:
a) C(s - graphite)
C (s-diamond)
J
b) 4 Ag + O₂ = 2 Ag₂O
R=631
Mal R

SrF2(s)
Sro(s)
SrS04(s)
Ti(g)
At 298K and 1 atm
(CH3)2CO(1)
C(s, diamond)
C(s, graphite)
C10H8(s) naphthalene
C12H26(1)
C2H2(g)
C2H4(g)
C2H5OH(1)
C2H6(g)
C2N2(g)
3H603(s) (lactic acid)
3H8(g)
H10(g)
H12(1) cyclohexane
H1206/c)
-1216.3
-592.0
-1445
473
O
AHf (kJ/mol)
-247.6
1.9
0
75.3
-350.9
227.4
52.4
-277.6
-84.0
308.9
-694.1
-103.8
-125.7
-156.2
-562.4
-1334
428.4
0
AGf (kJ/mol)
-155.7
2.9
0
201
28.1
209.9
68.4
-174.8
-32.0
297.2
82.1
55.5
122
180.3
30.6
-522.9
-23.4
-17.15
26.7
S (J/mol K)
200.4
2.38
5.74
166.9
490.6
200.9
219.3
160.7
229.2
242.3
142.3
270.3
310.1
204.3

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