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4) Given the same concentrations, the reaction CO(g) + Cl2(g)→ COC2(g) at 250°C is 1.50 x 10° times as fast as the same reaction at 150°C. Calculate the energy of activation (as kJ/mol) for this reaction. Assume that the frequency factor is constant. (R: 8.314 J/mol.K)

4) Given the same concentrations, the reaction CO(g) + Cl2(g)→ COC2(g) at 250°C is 1.50 x 10° times as fast as the same reaction at 150°C. Calculate the energy of activation (as kJ/mol) for this reaction. Assume that the frequency factor is constant. (R: 8.314 J/mol.K)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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4) Given the same concentrations, the reaction CO(g) + Cl2(g)→ COCI2(g) at 250°C is 1.50 x 10° times as fast as the same reaction at 150°C. Calculate the energy of activation (as kJ/mol) for this reaction. Assume that the frequency factor is constant. (R: 8.314 J/mol.K)
Transcribed Image Text:4) Given the same concentrations, the reaction CO(g) + Cl2(g)→ COCI2(g) at 250°C is 1.50 x 10° times as fast as the same reaction at 150°C. Calculate the energy of activation (as kJ/mol) for this reaction. Assume that the frequency factor is constant. (R: 8.314 J/mol.K)
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