4 Consider a Falcon 9, a two-state-to-orbit launch vehicle. The take-off mass of Falcon 9 is mto = 550,000 kg, the first stage fuel burn rate is m = 2500 kg/s over a maximum of 160 s, and constant thrust of T = 7500 kN. Making a lot of simplifying assumptions including constant gravity, no aerodynamic drag, thrust constant with altitude, we can approximate the vertical acceleration (assuming vertical thrust) as: ay(t) = T-mog+mgt mo-mt After 60 s, lets assumed that the rocket is turned by 45 deg so that the equations for acceleration become (assuming flat Earth, i.e., gravity is still in y-direction): az (t) = (T/√2) mo-mt ay(t) = (T/√2)-mog+mgt mo-mt Calculate the magnitude of velocity (in km/s) at t = 121 sec. (no answer) Correct Answer: 1.287

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Chapter1: Units, Trigonometry. And Vectors
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Consider a Falcon 9, a two-state-to-orbit launch vehicle. The take-off mass of Falcon 9 is mto = 550,000 kg, the first stage fuel burn rate is m = 2500 kg/s over a maximum of 160
s, and constant thrust of T = 7500 kN. Making a lot of simplifying assumptions including constant gravity, no aerodynamic drag, thrust constant with altitude, we can
approximate the vertical acceleration (assuming vertical thrust) as:
ay(t) =
T-mog+mgt
mo-mt
After 60 s, lets assumed that the rocket is turned by 45 deg so that the equations for acceleration become (assuming flat Earth, i.e., gravity is still in y-direction):
az (t) =
(T/√2)
mo-mt
(T/√2)-mog+mgt
ay(t) =
mo-mt
Calculate the magnitude of velocity (in km/s) at t = 121 sec.
(no answer)
Correct Answer: 1.287
Transcribed Image Text:4 Consider a Falcon 9, a two-state-to-orbit launch vehicle. The take-off mass of Falcon 9 is mto = 550,000 kg, the first stage fuel burn rate is m = 2500 kg/s over a maximum of 160 s, and constant thrust of T = 7500 kN. Making a lot of simplifying assumptions including constant gravity, no aerodynamic drag, thrust constant with altitude, we can approximate the vertical acceleration (assuming vertical thrust) as: ay(t) = T-mog+mgt mo-mt After 60 s, lets assumed that the rocket is turned by 45 deg so that the equations for acceleration become (assuming flat Earth, i.e., gravity is still in y-direction): az (t) = (T/√2) mo-mt (T/√2)-mog+mgt ay(t) = mo-mt Calculate the magnitude of velocity (in km/s) at t = 121 sec. (no answer) Correct Answer: 1.287
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