4-68. A 4.2-MeV photon is backscattered (0 = 1809 by a electron. (a) What is the wavelength of the scattered photon? (b) What is the kinetic energy of the electron?

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A: λsc=λi+λc1-cosθλi=λsc-λc1-cosθ=0.0830 nm-0.00242 nm1-cos180°=0.0782 nm

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A: work function (w) = 2.74 eV wavelength of incident photons = 415 nm

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Q: 4-68. A 4.2-MeV photon is backscattered (0= 1809 by a electron. (a) What is the wavelength of the…

A: Given that:-Angle, ϕ=180°Photon energy, E=4.2MeVWavelength of scattered photon, Assuming that the…