4 3 1 1 3 4 5 t (s) How far does the particle travel between t = 0 s and t = 6 s? It moves 6 meters It moves 24 meters It moves 12 meters O It does not move at all O It moves 4 meters (s/u) A
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- The figure shows the acceleration-time plot of an object. What is the acceleration of the object at time t = 5s. O 15 ft/s² O 6 ft/s² 0 ft/s² O 3 ft/s² v (ft/s) 30 16 10 23 -t (s)If A = (6 m)i - (8 m) ĵ then 47 has magnitude: O 10 m O 56 m O 40 m 0-8 m 08 mAn object is moving with position p(t). We know that p(4) = 12m, and p'(4) = 2 m/s . What is the approximate position of the object at time t = 5? At what time does t = 4.1 ?
- Two cars are initially (2.50+C) km apart on a straight road. If the cars are moving toward each other, car 1 with a speed of (5.40+A) m/s and car 2 with a speed of (7.20+B) m/s, how many seconds will it take before the cars meet? Round your answer to three significant figures. A=8 B=7 C=20HelpX An object velocity decreases from 15m/s to 10m/s in 2s. It's deceleration 0/1 is * 2.5 m/s^2 5 m/s^2 7.5 m/s^2 12.5 m/s^2
- 1.A conductor in a train travelling at 4.0 m/s (N) walks across the train at 1.2 m/s (E) to validate a ticket. If the trian car is 4.0m wide, how long does it take the conductor to reach the other side? vog=? vom 1.2 m/s(E) (1.2/4.2) vmg= 4.0 m/s(N) vog 4.2m/s(N17E) Ad At = Δυ At = 3.3s vom=5m/s(W) vmg=11m/s(S = 12m/s = vog vom+vmg -5m/s (W)+ 11m/s(S) = sqrt (5m/s)^2+ (1m/s)^2 sin 90 12m/s 4.0m/s 1.2m/s 2. A jetski speeds across a river at 11 m/s relative to the water. The jet ski's heading is South. The river is flowing West at 5m/s. Determine the jet ski's velocity relative to the shore. vog=? = vog vom+vmg sin 0 5m/s = 1.2m/s(E) + 4.0m/s(N) =sqrt (1.2m/s)^2 + (4.0m/s)^2 =4.2 m/s = 24° Therefore the answer is 12m/s (S24W) Tan-1= = 17A muon (an elementary particle) enters a region with a speed of 5.45 x 106 m/s and then is slowed at the rate of 1.30 x 1014 m/s². (a) How far does the muon take to stop? m (b) Graph x versus t for the muon. x (m) 0.12 0.10 0.08 0.06 0.04 0.02 O 0.12 0.10 0.08 0.06 0.04 0.02 O x (m) Graph v versus t for the muon. v (m/s) 6x106 5x10 4x10 3x106 2x106 O 1x106 10 v (m/s) 6x10 5x10 4x106 3x106 2x106 1x106 10 Enter a number. Additional Materials 10 20 10 20 20 30 20 30 6x 10p 5x10 LL 4x106 3x10 2x10 1x106 t (ns) 30 40 30 40 40 t (ns) 40 t (ns) t (ns) O x (m) 0.12 0.10 0.08 0.06 0.04 0.02 O x (m) 0.12 0.10 0.08 0.06 0.04 0.02 v (m/s) v (m/s) 6x10 5x10 4x106 3x106 2x106 1x106 10 10 10 20 10 20 20 30 20 30 30 30 -t (ns) 40 40 40 40 t (ns) t (ns) t (ns)You travel from point A to point B in a car moving at a constant speed of 70 km/h. Then you travel the same distance from point B to another point C, moving at a constant speed of 90 km/h. Is your average speed for the entire trip from A to C 80 km/h? Explain why or why not.
- Two locomotives 70 kilometers apart are travelling on the same track towards each other, Engine A moves at 22 kilometers per hour east and engine B moves at 13 kilometersper hour west. At the instant both trains begin moving, an annoying mutant fly beginsflying from engine A towards engine B at 33 kilometers per hour . The instant it touchesB, it turns around and flies back. It goes on this way until the two locomotives collideand the mutant fly is finally squashed. So, before its untimely demise, a) what is the total distance the fly flew? b) the time it took till it was eliminated and c) the average velocity of the fly? how can i find this please3. The graph below shows the displacement vs time of a student leaving the NSCI 110 after physics class walking towards the cafeteria for lunch (assume a 1-D motion) At some point between NSCI 110 and the cafeteria, the student realizes they have left their cell phone in the classroom, so they turn back to get it. Displacement vs Time 120 100 nol Velocity vs Time 80 1.5 60 40 30 60 90 120 150 180 210 20 -1.5 30 60 90 120 150 180 210 Time (s) a. How far did the student walk before realizing that they left their cell phone in the classroom? How long did this take? (2 marks) b. With what velocity did the student walk back to the classroom? (2 marks) c. Fill out the velocity vs time graph above. (2 marks) Distance (m)10) An object has a position given by [2.0 m+ (5.00 m/s)] + [3.0 m - 2.00 m/s2)/2, where quantities 7 are in SI units. What is the speed of the object at time -2.00 s? 10) A) 7.65 m/s B) 7.00 m/s C) 13.0 m/s D) 6.40 m/s E) 9.43 m/s