3kQ 1kQ 2kQ 5kQ 6V -1.5V 2)Using Kirchhoff's Current Law and Kirchhoff's Voltage Law a) how KCL can be applied to the central extraordinary node b) determine the current leaving the positive terminal of the 6V source and the current leaving the positive terminal of the 1.5V source. Also, explain what the sign of the current leaving the 1.5V source means. c) how KVL can be applied to two of the loops in the circuit. Be sure to indicate which loops you are applying the law to, and how you determine the various voltage values.

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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3kQ
1kQ
2kQ
5kQ
=6V
-1.5V
2)Using Kirchhoff's Current Law and Kirchhoff's Voltage Law
a) how KCL can be applied to the central extraordinary node
b) determine the current leaving the positive terminal of the 6V source and the current leaving
the positive terminal of the 1.5V source. Also, explain what the sign of the current leaving the
1.5V source means.
c) how KVL can be applied to two of the loops in the circuit. Be sure to indicate which loops you
are applying the law to, and how you determine the various voltage values.
Transcribed Image Text:3kQ 1kQ 2kQ 5kQ =6V -1.5V 2)Using Kirchhoff's Current Law and Kirchhoff's Voltage Law a) how KCL can be applied to the central extraordinary node b) determine the current leaving the positive terminal of the 6V source and the current leaving the positive terminal of the 1.5V source. Also, explain what the sign of the current leaving the 1.5V source means. c) how KVL can be applied to two of the loops in the circuit. Be sure to indicate which loops you are applying the law to, and how you determine the various voltage values.
Expert Solution
Step 1

Electrical Engineering homework question answer, step 1, image 1

Kirchhoff’s Current Law

the algebraic sum of ALL the currents entering and leaving a junction must be equal to zero as  Σ IIN = Σ IOUT

We Apply kcl at A node

Here

 I1=I2+I5

Electrical Engineering homework question answer, step 1, image 2

 

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