38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working moth who do not have enough money to cover their health insurance deductibl Complete parts (a) through (c) below.
38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working moth who do not have enough money to cover their health insurance deductibl Complete parts (a) through (c) below.
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.5: Interpreting Data
Problem 3E
Related questions
Question
Transcribed Image Text:### Problem Context
38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles.
### Task
Complete parts (a) through (c) below.
#### (a) Construct a Binomial Distribution
- Parameters: \( n = 6 \) and \( p = 0.38 \)
The table to be filled is as follows:
| x | P(x) |
|---|-------|
| 0 | |
| 1 | |
| 2 | |
| 3 | |
| 4 | |
| 5 | |
| 6 | |
*(Round to the nearest thousandth as needed.)*
Expert Solution
Step 1: Given information
It is given that 38% of working mothers do not have enough money to cover their health insurance deductibles i.e. probability that a working mothers do not a enough money to cover health insurance = p = 0.38
We randomly select six working mothers, i.e. n = 6
Therefore, we can say X ~ Binomial (n= 6, p = 0.38); X= 0,2,3,4,5,6
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