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38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working moth who do not have enough money to cover their health insurance deductibl Complete parts (a) through (c) below.

38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working moth who do not have enough money to cover their health insurance deductibl Complete parts (a) through (c) below.

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter11: Data Analysis And Displays
Section11.1: Measures Of Center And Variation
Problem 31E
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### Problem Context 38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. ### Task Complete parts (a) through (c) below. #### (a) Construct a Binomial Distribution - Parameters: \( n = 6 \) and \( p = 0.38 \) The table to be filled is as follows: | x | P(x) | |---|-------| | 0 | | | 1 | | | 2 | | | 3 | | | 4 | | | 5 | | | 6 | | *(Round to the nearest thousandth as needed.)*
Transcribed Image Text:### Problem Context 38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. ### Task Complete parts (a) through (c) below. #### (a) Construct a Binomial Distribution - Parameters: \( n = 6 \) and \( p = 0.38 \) The table to be filled is as follows: | x | P(x) | |---|-------| | 0 | | | 1 | | | 2 | | | 3 | | | 4 | | | 5 | | | 6 | | *(Round to the nearest thousandth as needed.)*
Expert Solution
Step 1: Given information

It is given that 38% of working mothers do not have enough money to cover their health insurance deductibles i.e. probability that a working mothers do not a enough money to cover health insurance = p = 0.38 

We randomly select six working mothers, i.e. n = 6

Therefore, we can say X ~ Binomial (n= 6, p = 0.38); X= 0,2,3,4,5,6


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