athessMost Watched Ani...A pharmaceutical company claims their new diabetes medication results in less variance in apatient's glucose level than if the patient were on no medication at all. An endocrinologist wishes totest this claim. She divides participants randomly into two groups. Group A consists of 20 diabeticswho received the medication; group B consists of 26 diabetics who received a placebo. After twoweeks, the blood sugar level of each patient in each group was measured with the following results(in mg/dL):Group A:77.8, 229.4, 199.9, 110.1, 180.2, 116.1, 139.7, 171.1, 37.4, 158.1, 88.4, 195.5, 246.1, 142.4, 178.1,105.5, 179.6, 146.1, 78.8, 123.7Group B:124.5, 130.1, 136, 162.8, 113.4, 72.8, 142.6, 50.3, 179.8, 197, 230, 194.3, 171, 109.3, 114.4, 107.5,114.7, 195.3, 127.7, 126.4, 85.6, 166.7, 182.3, 113.5, 216.7, 162.8Ho:Perform a hypothesis test using a 6% level of significance to test the pharmaceutical company'sclaim.Step 1: State the null and alternative hypotheses.H₂:EV 1Watch Invincible S...V 1(So we will be performing a left-tailedWe will use a(n) FdfA= 19Part 2 of 4Step 2: Assuming the null hypothesis is true, determine the features of the distribution oftest statistics.p-value = 0.8103Step 3: Find the p-value of the test statistic.P(FSV 1.45070Chinese bureaucratsot western elementscal skill while retaining✓and denominator degrees of freedom dƒB = 25✓✓distribution with numerator degrees of freedomA = 145.2✓✓test.)SA 53.84✓Pokemon Jigglypu...s²F = =14507083=0.8103Step 4: Make a Conclusion About the null hypothesis.Since the p-value = 0.810308598606662 0.1897IB = 143.365SB 44.7005Yxa, we do not rejectYPart 3 of 4Part 4 of 4✓✓the null hypothesis.We cannot conclude that the medication results in lower variance in a diabetic's blood sugar levels.OWe conclude that the medication results in lower variance in a diabetic's blood sugar levels.tokyo L

Given that, A pharmaceutical company claims their new diabetes medication results in less variance…

Answered: Step 4: Make a Conclusion About the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(7) We are interested in whether the mean blood pressure for women is equal to the mean blood pressure for men or whether these two means are different. The null hypothesis is that these two means are equal. If they are different we have no prior view as to whether women or men have the higher mean blood pressure. We took a sample of the blood pressures of 16 women (group 1) and found an average blood pressure x1 of 119.4. We also measured the blood pressures of their respective brothers (group 2) and found an average blood pressure x 2 of 121.2. In order to carry out the relevant t test we calculated s?a to be 25. We choose a Type I error value a = 0.05. Calculate the numerical value of whichever test statistic you prefer (there are two possibilities). Given your choice of test statistic, state the relevant critical point(s). Carry out the test, indicating whether you accept or reject the null hypothesis.
Question #2
In my regression output using Hayes Model 1 I have the following results. Would it be safe to say that the following assumption is correct? 95% CI is [.036, .196] not statistically significant, But given that (p = .176) is greater than p=.005, we reject the null hypothesis. (b3) of .080, t = 1.36, p = .176, 95% CI [.036, .196].
Consider the simple linear regression model Y = B1 + B2X + e, and let b2 be the estimate for B2 and Var (b2) its estimated variance. Suppose we are intere the null hypothesis Ho : B2 = 0 at a level a = 0.05. Which of the following statements is false? O a. If we reject the null hypothesis that Ho : B2 = 0 against the alternative H1 : B2 # 0, then we will also reject against the alternative H1 : B2 0 but not against the alternative H : B2 # 0. O c. If we reject the null hypothesis that Ho : B2 = 0 against the alternative H1 : B2 0. O d. It is possible that we reject the null hypothesis Ho : B2 = 0 against the alternative H1 : B2 # 0 but not against the alternative H1 : B2 > 0. Clear my choice
4.
A mad scientist is interested in seeing if there is a relationship between the number of nights until the full moon (X) and the number of Werewolves (Y) that are caught by his assistant Igor. For the data below, compute a Pearson correlation (r) hypothesis test. Because one is not particularly cautious with mad science, the mad scientist is using a two-tailed test, α = .05. Be sure to show all work. Nights until the full moon (X) # of Werewolves caught (Y) 7 1 6 2 2 4 3 5 2 8 1 State the mad scientist’s null and alternative hypotheses 2 Find the critical r 3 Compute the observed r from the sample data 4 Make a statistical decision and a conclusion in everyday language
Question 11 The null hypothesis (HO) in a medical study states that a new drug has no effect on a specific condition. If the p-value is 0.02, what can we conclude at a significance level of 0.05? O a. Reject the null hypothesis Therefore, there is no evidence that the drug has an effect. O b. Fail to reject the null hypothesis. Therefore, there is strong evidence that the drug has an effect. O c. Fail to reject the null hypothesis. Therefore, there is no evidence that the drug has an effect. O d. Reject the null hypothesis. Therefore, there is strong evidence that the drug has an effect.
I keep getting the resulting pearson residuals and chi-square test-statistic wrong.
Suppose you are conducting an experiment, and you have 8 different treatments you are testing on lab mice. Assume that the outcome is a continuous random variable, and your main research question is whether or not the distribution of the outcome differs across treatment groups. You notice that the within group standard deviations differ greatly from one group to the next. Which of the following analytical approaches would be advisable to take in this situation? Question 23 options: Conduct a simple linear regression between the outcome and the treatment group assignment. Conduct an ANOVA followed by post-hoc Bonferroni adjustment. Conduct a Kruskal-Wallis test Calculate within-group Spearman correlations.
A researcher wonders if a “majority” of all residents of a particular city were in favor of a newly proposed city ordinance. Her hypotheses are H0: p = 0.5 versus Ha: p > 0.5. She collected data from a large enough random sample of residents (in order to use the normal approximation), and the resulting sample proportion was 0.41. The researcher has a few interns working on this project and has asked them to conduct the appropriate test and report an approximate p-value. Unfortunately, she received three different p-values from her interns: Chris reported a p-value of 0.08 Jamie reported a p-value of 0.41 Taylor reported a p-value of 0.62 A. Which of her interns reported a reasonable p-value? Explain. Hint: The precise p-value cannot be computed here, but you can eliminate interns' guesses. B. Use the p-value from part (a) to determine if a majority of all residents of the city were in favor of a newly proposed city ordinance.
As we noted previously, even a very small effect can be significant if the sample is large enough. Suppose, for example, that a researcher obtains a correlation of r = .60 for a sample of n =10 participants. Is this sample sufficient to conclude that a significant correlation exists in the population? Use a two-tailed test with α = .05. Based on the previously provided correlation, would you reject the null hypothesis established
You have determined that in the past three years there 7 of the 14 were hand injuries. Previous projections had indicated that under normal conditions, only four hand injuries were expected and 12 other injuries were expected. The remaining injuries were due to other causes. Calculate the chi-square value and discuss whether there was a significant difference in observed data vs. the expected data. Also discuss how the process of hypothesis testing might prove helpful o = 7 hand injuries and 7 other injuriese = 4 expected hand injuries and 12 other injuries

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Step 4: Make a Conclusion About the null hypothesis. Since the p-value= 0.81030859860666 2 0.1897 xa, we do not reject Part 4 of 4 the null hypothesis. We cannot conclude that the medication results in lower variance in a diabetic's blood sugar levels.