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37. A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) = N2(g) + 3H2(g) At equilibrium, it was found that the concentration of H2 was 0.0283 M, the concentration of N2 was 0.00944 M, and the concentration of NH3 was 0.101 M. What is K, for this equilibrium? (R= 0.0821 L atm/(K • mol)) A) 4.28 B) C) 2.85 1.70 x 10-2 D) 1.95 x 10-8

37. A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) = N2(g) + 3H2(g) At equilibrium, it was found that the concentration of H2 was 0.0283 M, the concentration of N2 was 0.00944 M, and the concentration of NH3 was 0.101 M. What is K, for this equilibrium? (R= 0.0821 L atm/(K • mol)) A) 4.28 B) C) 2.85 1.70 x 10-2 D) 1.95 x 10-8

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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37. A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) = N2(g) + 3H2(g) At equilibrium, it was found that the concentration of H2 was 0.0283 M, the concentration of N2 was 0.00944 M, and the concentration of NH3 was 0.101 M. What is K, for this equilibrium? (R= 0.0821 L. atm/(K • mol)) A) 4.28 B) C) 2.85 1.70 x 10-2 D) 1.95 × 10-8
Transcribed Image Text:37. A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) = N2(g) + 3H2(g) At equilibrium, it was found that the concentration of H2 was 0.0283 M, the concentration of N2 was 0.00944 M, and the concentration of NH3 was 0.101 M. What is K, for this equilibrium? (R= 0.0821 L. atm/(K • mol)) A) 4.28 B) C) 2.85 1.70 x 10-2 D) 1.95 × 10-8
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