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- -A ZE The potential difference between the accelerating plates of a TV set is about 30 kV. If the distance between the plates is 1.3 cm, find the magnitude of the uniform electric field in the region between the plates. N/CMY N An electron is to be accelerated in a uniform electric field having a strength of 1.90 x 106 v/m. (a) What energy in kev is given to the electron if it is accelerated through 0.790 m? kev (b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV (as in the Stanford Linear Accelerator, which is actually smaller than this)? km Additional MaterialsWhich of the following statements is false for a conductor in electrostatic equilibrium. a. The charge on the conductor is always distributed uniformly throughout the conducting material b. The electric potential inside the conductor is constant. c. The electric field at the surface of the conductor is perpendicular to the surface everywhere. d. The electric field inside the conducting material is zero. e. Any excess charge resides solely on the surface of the conductor.
- Attached is the question and diagram.A fuel-efficient car is able to convert the chemical potential energy of gasoline into translational kinetic energy at an efficiency of 78.4%. If there is 8742 kJ of chemical potential energy in one tank of gas, what is the amount of translational kinetic energy produced. How to manipulate formula eff=output/input x 100Two large parallel copper plates are 7.39 cm apart and have a uniform electric field of magnitude E = 3.44 N/C between them (see the figure). An electron is released from the negative plate at the same time that a proton is released from the positive plate. Neglect the force of the particles on each other and find their distance from the positive plate when they pass each other. Positive Negative plate plate P E Number i Units
- Cathode ray tubes (CRTS) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.38 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates. HINT V/m4