30. The expression for the equilibrium constant for the following reaction. 2H,S) =2H%e) +S%e) is 2(8) [H,F[s,] [H,s} Kc = Ke = If (H,s]= 4.84x10*moldm³, [H,]=1.50x10moldm and the equilibrium constant for the reaction is 2.25 x 10“. Calculate the [S2] at equilibrium. A 2.25 x 103 В в 3.5х 3.5 x 103 C 4.84 x 103 D 2.34 x 103 D
30. The expression for the equilibrium constant for the following reaction. 2H,S) =2H%e) +S%e) is 2(8) [H,F[s,] [H,s} Kc = Ke = If (H,s]= 4.84x10*moldm³, [H,]=1.50x10moldm and the equilibrium constant for the reaction is 2.25 x 10“. Calculate the [S2] at equilibrium. A 2.25 x 103 В в 3.5х 3.5 x 103 C 4.84 x 103 D 2.34 x 103 D
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Select the best pair of answer below justifying the reason for your choice.
![30.
The expression for the equilibrium constant
for the following reaction.
2H,S) = 2He) + Sle) is
Ke = H.F[s.]
[H,s}
If [H,s]= 4.84x10- moldm,
[H,]=1.50x10 moldm and the
equilibrium constant for the reaction is
2.25 x 104. Calculate the [S2] at equilibrium.
А 2.25 х 10°
3.5 x 103
C 4.84 x 103
2.34 x 103
В](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5adc4cb7-305b-4067-a31a-706a4336ac3c%2Fb9ff2e7b-88c3-455b-aa8b-269877ebfb31%2Fh7vbgpe_processed.png&w=3840&q=75)
Transcribed Image Text:30.
The expression for the equilibrium constant
for the following reaction.
2H,S) = 2He) + Sle) is
Ke = H.F[s.]
[H,s}
If [H,s]= 4.84x10- moldm,
[H,]=1.50x10 moldm and the
equilibrium constant for the reaction is
2.25 x 104. Calculate the [S2] at equilibrium.
А 2.25 х 10°
3.5 x 103
C 4.84 x 103
2.34 x 103
В
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