3.In one section of the irrigation canal, the narrowing of 1.5 times the width upstream (asshown in the figure below). If the uniform channel cross section is rectangular with thedownstream width (b2) = 4.5 m, the velocity (V1) and depth (y1) of the upstream flow aremeasured to be 0.2 m/s and 4.0 m, determine the energy loss (hf ) due to channel narrowingif the downstream flow depth is assumed to be the same as the upstream flow depth !b2bịV1

Answered: Image /qna-images/answer/3daaf13c-1b4c-40f3-97cd-b187f3e76aa6.jpg

Answered: 3.In one section of the irrigation…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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In the vertical wall of a reservoir (A) there is a drowned hole that it flows into another reservoir (B) with a real discharge speed of 4,5m/s. This one reservoir (B), in turn, has a square orifice with free discharge of the form shown in the figure. It requires a flow of 0,089 m³/s and there is no overflow of the system, determine the head loss in both orifices. (See the image) Data: Orifice diameter 1 = 0,2m; Discharge coefficient for orifice 2 = 0,604; contraction coefficient for orifice 2 = 0,64. Consider both holessmall in relation to the depth of the reservoirs.
In Fig. let y1 = 6 ft and the gate width b= 8 ft.Find the gate opening H that would allow a free-dischargefl ow of 30,000 gal/min under the gate.
Water flows in a rectangular channel that is 0.5 m wide as shown. The upstream depth is 70 mm. The water surface rises 40 mm as it passes over a portion where the channel bottom rises 10 mm. If viscous effects are negligible. What is the flow rate? (2) 100 mm (1) 70 mm 10 mm
Please answer these 2 questions. Only final answer needed. Please fast.
Fast plz
Fluid Mechanics: Open Channel Flow
Water flows steadily along a horizontal open channel of uniform width, over a broad-crested weir. The channel bed upstream from the weir (to the left) is d metres above the channel bed downstream from the weir (to the right), as shown in the figure below. The volume flow rate per unit width is Q = 6 m? s-1, and upstream the depth of the water is h1 = 3 m. Take the magnitude of the acceleration due to gravity as g = 10 ms 2. hi D p. h2 U2 (a) Find the upstream speed u1, and show that the flow is subcritical there. (b) Find the specific energy E (in m) for the flow upstream. (c) By applying Bernoulli's equation along a suitable streamline, show that the depth h2 in the downstream section of the channel satisfies the equation 5h – (16 + 5d)h+9 = 0.
88 cm d 17 cm In the fountain shown, water flowing at 35 lpm exits the weir at the top, with a stream that is 17 cm wide and 0.20 cm thick. Determine the diameter of the stream (cm) at a point 88 cm below the weir, assuming that the flow has a cylindrical shape at this location Solution: 1.3 cm
The tank shown drains through a triangular weir whose flowrate is described by the equation given. Determine the time it will take for the tank to drain from completely full (h = 5 ft) to 5.25 feet deep (h = 0.25 ft) assuming there is no flow into the tank. Volumetric Flowrate h=5 ft + 5 ft 3 ft³ S = 2.48 h².5 (for h in feet) 10 ft -20 ft- -20 ft-
A rectangular channel 6 m wide with a depth of flow of 3 m has a mean velocity of 1.5 m/s. The channel undergoes a smooth, gradual contraction to a width of 4.5 m. Calculate the net fluid force on the walls and floor of the contraction in the flow direction.
Parvinbhai
Q4: water flows steadily through the large tanks shown in figure below. Determine the water depth, ha. (30 mark) (1) hA 0.03 -m diameter (2) |(3) hg = 2 m 0.05 - m diameter (4) B

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