As shown in the figure below, at the entrance to a 3-ft-wide channel the velocity distribution is uniform with a velocity V. Further downstream the velocity profile is given by u = 4y - 2y2, where u is in ft/s and y is in ft. Determine the value of V. Assume h = 0.93 ft.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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As shown in the figure below, at the entrance to a 3-ft-wide channel, the velocity distribution is uniform with a velocity \( V \). Further downstream, the velocity profile is given by \( u = 4y - 2y^2 \), where \( u \) is in ft/s and \( y \) is in ft. Determine the value of \( V \).

Assume \( h = 0.93 \) ft.

**Diagram Explanation:**

The diagram illustrates the channel with annotations highlighting different sections and velocity distributions. The left section shows a uniform velocity \( V \) across a width of 0.75 ft. The right section displays a velocity profile given by the equation \( u = 4y - 2y^2 \). The water height \( h \) is marked as 0.93 ft. 

Calculate \( V \):

\[ V = \boxed{\phantom{answer}} \] ft/s
Transcribed Image Text:As shown in the figure below, at the entrance to a 3-ft-wide channel, the velocity distribution is uniform with a velocity \( V \). Further downstream, the velocity profile is given by \( u = 4y - 2y^2 \), where \( u \) is in ft/s and \( y \) is in ft. Determine the value of \( V \). Assume \( h = 0.93 \) ft. **Diagram Explanation:** The diagram illustrates the channel with annotations highlighting different sections and velocity distributions. The left section shows a uniform velocity \( V \) across a width of 0.75 ft. The right section displays a velocity profile given by the equation \( u = 4y - 2y^2 \). The water height \( h \) is marked as 0.93 ft. Calculate \( V \): \[ V = \boxed{\phantom{answer}} \] ft/s
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