Please answer these 2 questions. Only final answer needed. Please fast. An evaporative cooling tower (see the figurebelow) is used to cool water from 107 to 75 °F.Water enters the tower at a rate of m1Ibm/hr. Dry air (no water vapor) flows into thetower at a rate of mz = 145000 Ibm/hr. If therate of wet air flow out of the tower is m2 == 275000150200 Ibm/hr, determine(a) the rate of water evaporation in Ibm/hr,(b) the rate of cooled water flow in Ibm/hr.Wet airm = m,Warm waterm = m,Dry air →m = m,Cooledwater(a) mwiIbm/hr(b) m =iIbm/hr Current Attempt in ProgressAs shown in the figure below, at the entrance to a3-ft-wide channel the velocity distribution isuniform with a velocity V. Further downstream thevelocity profile is given by u = 4y - 2y², where u is inft/s and y is in ft. Determine the value of V.Assume h = 0.86 ft.yhu = 4y – 2y20.75 ftV =ift/s

Given Data Water flow rate, m1=275000 lbm/hr dry air flow rate, m3=145000 lbm/hr wet air flow rate,…

Answered: An evaporative cooling tower (see the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Concept explainers

Question

Please answer these 2 questions. Only final answer needed. Please fast.

An evaporative cooling tower (see the figure
below) is used to cool water from 107 to 75 °F.
Water enters the tower at a rate of m1
Ibm/hr. Dry air (no water vapor) flows into the
tower at a rate of mz = 145000 Ibm/hr. If the
rate of wet air flow out of the tower is m2 =
= 275000
150200 Ibm/hr, determine
(a) the rate of water evaporation in Ibm/hr,
(b) the rate of cooled water flow in Ibm/hr.
Wet air
m = m,
Warm water
m = m,
Dry air →
m = m,
Cooled
water
(a) mw
i
Ibm/hr
(b) m =
i
Ibm/hr

Transcribed Image Text:Current Attempt in Progress As shown in the figure below, at the entrance to a 3-ft-wide channel the velocity distribution is uniform with a velocity V. Further downstream the velocity profile is given by u = 4y - 2y², where u is in ft/s and y is in ft. Determine the value of V. Assume h = 0.86 ft. y h u = 4y – 2y2 0.75 ft V = i ft/s

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions