3.24 Problem: Two plates 75 mm x 12 mm thick are joined with a triple riveted butt joint as shown in the figure 3.24. Cover plates are of unequal lengths. Assume diameter of rivet hole to 2 mm bigger than rivet diam. Ⓒ 2 3 Allowable Stresses: Tension = 148 MPa Shearing stress = 110 MPa Bearing stress = 220 MPa Compute the strength of the joint on the basis of rivet values. Compute the strength of the joint on the basis of failure of plates. Compute the efficiency of the joint. 7 5u 20 m 22 7.5mm Q 25mm 22 mm M 13
3.24 Problem: Two plates 75 mm x 12 mm thick are joined with a triple riveted butt joint as shown in the figure 3.24. Cover plates are of unequal lengths. Assume diameter of rivet hole to 2 mm bigger than rivet diam. Ⓒ 2 3 Allowable Stresses: Tension = 148 MPa Shearing stress = 110 MPa Bearing stress = 220 MPa Compute the strength of the joint on the basis of rivet values. Compute the strength of the joint on the basis of failure of plates. Compute the efficiency of the joint. 7 5u 20 m 22 7.5mm Q 25mm 22 mm M 13
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Subject: Steel design- Bolted Steel Connection
*Use NSCP 2015 formula/guide to solve this problem
*Use Handwritten

Transcribed Image Text:3.24 Problem:
Two plates 75 mm x 12 mm thick are joined with a triple riveted butt joint as shown in
the figure 3.24. Cover plates are of unequal lengths. Assume diameter of rivet hole to
2 mm bigger than rivet diam.
2
Allowable Stresses:
Tension 148 MPa
Shearing stress = 110 MPa
Bearing stress 220 MPa
=
=
Compute the strength of the joint
on the basis of rivet values.
Compute the strength of the joint
on the basis of failure of plates.
Compute the efficiency of the
joint.
T SO
20 mm
7.5
22 sta
22 mm M
Figure 3.24
13new
H
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