3.2 A car starts from rest and accelerates with a constant force of 1000 N. Suppose the resisting force due to a number of factors is F₁-6v(t) N, where v(t) is the velocity of the car at time t. If the mass of the car together with its driver is 1200 kg. Which of the following options describes the relationship between v and t? a) [e200t. v(t)]' = 500 200€ b) [e-200t.v(t)]' = 500 500-200t c) [e=¹ . v(t)] ′ = =e=² 200 d) [e=². v(t)] ' = e = ² 200 = 200
3.2 A car starts from rest and accelerates with a constant force of 1000 N. Suppose the resisting force due to a number of factors is F₁-6v(t) N, where v(t) is the velocity of the car at time t. If the mass of the car together with its driver is 1200 kg. Which of the following options describes the relationship between v and t? a) [e200t. v(t)]' = 500 200€ b) [e-200t.v(t)]' = 500 500-200t c) [e=¹ . v(t)] ′ = =e=² 200 d) [e=². v(t)] ' = e = ² 200 = 200
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![3.2 A car starts from rest and accelerates with a constant force of 1000 N. Suppose the resisting
force due to a number of factors is FR-6v(t) N, where v(t) is the velocity of the car at time t. If the
mass of the car together with its driver is 1200 kg. Which of the following options describes the
relationship between v and t?
500
a) [e200t. v(t)]' = €200t
3
500
-200€. v(t)]'
b) [e-2
-200t
-
e
3
c) 200
[em². v(t)] = = ext
t
200
d)
· [e= = ² · v(t)]' = = e == ²
200
200](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb9027ed-a7cd-4af9-80b3-ae2c1df1d725%2F2aa28c20-8f94-4013-b581-b804a0913f61%2Fot0v3za_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.2 A car starts from rest and accelerates with a constant force of 1000 N. Suppose the resisting
force due to a number of factors is FR-6v(t) N, where v(t) is the velocity of the car at time t. If the
mass of the car together with its driver is 1200 kg. Which of the following options describes the
relationship between v and t?
500
a) [e200t. v(t)]' = €200t
3
500
-200€. v(t)]'
b) [e-2
-200t
-
e
3
c) 200
[em². v(t)] = = ext
t
200
d)
· [e= = ² · v(t)]' = = e == ²
200
200
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