An electron is a subatomic particle (m= 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +7.94 x 105 m/s to a final velocity of 1.93 x 106 m/s while traveling a distance of 0.0278 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.47 x 10-17 N, and F₂, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. (a) Number (b) Number i i Units Units F₁ v
An electron is a subatomic particle (m= 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +7.94 x 105 m/s to a final velocity of 1.93 x 106 m/s while traveling a distance of 0.0278 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.47 x 10-17 N, and F₂, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. (a) Number (b) Number i i Units Units F₁ v
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Chapter1: Units, Trigonometry. And Vectors
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![An electron is a subatomic particle \((m = 9.11 \times 10^{-31} \text{ kg})\) that is subject to electric forces. An electron moving in the \(+\text{x}\) direction accelerates from an initial velocity of \(+7.94 \times 10^{5} \text{ m/s}\) to a final velocity of \(1.93 \times 10^{6} \text{ m/s}\) while traveling a distance of 0.0278 m. The electron's acceleration is due to two electric forces parallel to the x-axis: \(\overrightarrow{F}_1 = 7.47 \times 10^{-17} \text{ N}\), and \(\overrightarrow{F}_2\), which points in the \(-\text{x}\) direction.
Find the magnitudes of (a) the net force acting on the electron and (b) the electric force \(\overrightarrow{F}_2\).
- (a) Number: [ ] Units: [ ]
- (b) Number: [ ] Units: [ ]
**Diagram Explanation:**
The diagram shows two forces acting on an electron. The electron is initially moving to the right (positive x-direction) with velocity \(v_0\).
- \(\overrightarrow{F}_1\) is depicted as a blue arrow pointing to the right (positive x-direction).
- \(\overrightarrow{F}_2\) is depicted as a blue arrow pointing to the left (negative x-direction).
- The initial velocity (\(v_0\)) and final velocity (\(v\)) of the electron are represented by red arrows along the x-axis.
- The distance traveled, \(x\), is indicated as the horizontal distance between the initial and final positions of the electron.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd452bd8c-7554-4806-a6d8-accf0f380aea%2Fa7f4ab78-163b-4390-b92a-99ec858e9769%2Fe1eeq5l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An electron is a subatomic particle \((m = 9.11 \times 10^{-31} \text{ kg})\) that is subject to electric forces. An electron moving in the \(+\text{x}\) direction accelerates from an initial velocity of \(+7.94 \times 10^{5} \text{ m/s}\) to a final velocity of \(1.93 \times 10^{6} \text{ m/s}\) while traveling a distance of 0.0278 m. The electron's acceleration is due to two electric forces parallel to the x-axis: \(\overrightarrow{F}_1 = 7.47 \times 10^{-17} \text{ N}\), and \(\overrightarrow{F}_2\), which points in the \(-\text{x}\) direction.
Find the magnitudes of (a) the net force acting on the electron and (b) the electric force \(\overrightarrow{F}_2\).
- (a) Number: [ ] Units: [ ]
- (b) Number: [ ] Units: [ ]
**Diagram Explanation:**
The diagram shows two forces acting on an electron. The electron is initially moving to the right (positive x-direction) with velocity \(v_0\).
- \(\overrightarrow{F}_1\) is depicted as a blue arrow pointing to the right (positive x-direction).
- \(\overrightarrow{F}_2\) is depicted as a blue arrow pointing to the left (negative x-direction).
- The initial velocity (\(v_0\)) and final velocity (\(v\)) of the electron are represented by red arrows along the x-axis.
- The distance traveled, \(x\), is indicated as the horizontal distance between the initial and final positions of the electron.
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