A particle with a charge of 5.50 nC is moving in a uniform magnetic field of B = -(1.29 T). The magnetic force on the particle is measured to be F ¹= −( 4.00×10-7 N )+(7.60×10-7 N) 3.
A particle with a charge of 5.50 nC is moving in a uniform magnetic field of B = -(1.29 T). The magnetic force on the particle is measured to be F ¹= −( 4.00×10-7 N )+(7.60×10-7 N) 3.
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p lease just part b
Transcribed Image Text:A particle with a charge of - 5.50 nC is moving in a
uniform magnetic field of B = −( 1.29 T )Ê. The
magnetic force on the particle is measured to be
F = −( 4.00×10¯7 N )î+( 7.60×10−7 N )ĵ.
Transcribed Image Text:Are there components of the velocity that cannot be determined by measuring the force?
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yes
no
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Part B
Calculate the x component of the velocity of the particle.
Express your answer in meters per second to three significant figures.
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ΤΙ ΑΣΦ
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?
V₂ =
102
Correct
m/s
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C too please!
Transcribed Image Text:Part C
Calculate the y component of the velocity of the particle.
Express your answer in meters per second to three significant figures.
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1ΨΕΙ ΑΣΦ
www ?
Vy
Submit
||
m/s
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