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3. What would be the electric field at (x, y) = (2m, 0.4m) if the electric potential is given by V(x, y) = (5V/m³)x²y –
(8V/m*)æy²,
4. If q1 = 4 nC, q2 = –7.8 nC and q3 = 2.4 nC, Find the net electric flux through each of the surface S1, S2, S3, S4 and
S5.

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8. Figure below shows a ring of outer radius R = 13.0 cm and inner radius l'inner = 0.200R. It has uniform surface charge density 0 = 6.20 pC/m². With V = 0 at infinity, find the electric potential at point P on the central axis of the ring, at distance z = 2.00R from the center of the ring. 6 dQ K √ ₁7 - Pl What is your dQ? What is your infinitesimal area element? (a) Start with the formula for the potential: V = k What are your vectors r and r'? What is the distance to point P? What is dV? Potential due to a small ring of charge on the disk? (b) Write out the integral that you need to compute to get V. What are the bounds? (c) Once you get an expression for V, solve numerically. (d) Check to see if the units of your expression makes sense for V.
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.The electric potential (voltage) in a particular region of space is given by: V(x,y,z) = { K(x³z? - y5) + C)} Where, in the above function, r= (x2 + y2 + z2)% and Kand C are constants... alculate the components of the electric field, Ex, Ey, E,.
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4. Having found the voltage difference from knowing the electric field, we can also do the inverse, find the electric field if we know the voltage as a function of position. Since the inverse of integration is differentiation, we have: av Ey ây' The partial derivative OV/Ox means that to take the derivative with respect to x while treating y and z as constant. The electric potential in a region of space is given by Ex = What is the electric field in this region? av Əx' 2 5y V (x, y, z) = V. ((-)² – 57) av əz
O:11)
4. Figure below shows a ring of outer radius R = 13.0 cm, inner radius r= 0.200R, and uniform surface charge density o = 6.20 pC/m2. With V = 0 at infinity, find the electric potential at point P on the central axis of the ring, at distance z = 2.0OR from the center of the ring. %3D R