3. We can estimate the dipole moment of a strongly polar diatomic molecule by saying the charges are te (where e = 1.6 x 10-19 C) and the spacing is about one atom width say 2x10-10 m. How large a derivative of E (dE/dx) is necessary to overcome gravity for this dipole? Say that the molecular weight of such a molecule is 18 (like water is). This makes the mass of this 18 times the proton mass, roughly. Is this dE/dx easily made in the laboratory? Explain

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3. We can estimate the dipole moment of a strongly polar diatomic molecule by saying
the charges are te (where e = 1.6 x 10-19 C) and the spacing is about one atom width
say 2x10-10 m. How large a derivative of E (dE/dx) is necessary to overcome gravity for
this dipole? Say that the molecular weight of such a molecule is 18 (like water is). This
makes the mass of this 18 times the proton mass, roughly. Is this dE/dx easily made in
the laboratory? Explain
Transcribed Image Text:3. We can estimate the dipole moment of a strongly polar diatomic molecule by saying the charges are te (where e = 1.6 x 10-19 C) and the spacing is about one atom width say 2x10-10 m. How large a derivative of E (dE/dx) is necessary to overcome gravity for this dipole? Say that the molecular weight of such a molecule is 18 (like water is). This makes the mass of this 18 times the proton mass, roughly. Is this dE/dx easily made in the laboratory? Explain
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