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- The instantaneous power absorbed by the load in a single-phase ac circuit, for a general R LC load under sinusoidal-steady-state excitation. is (a) Nonzero constant (b) Zero (c) Containing double-frequency components2. Two transformes A and B of ratings 5uokVA and 25okVA. Supplying a load kVA of 750 ato.8Pf lagging. open circunt valtajes are 400V and 410v respectively. Trusfarmn A has 1/ nsistance and 5/ ractance and traugformer B hay 1.$, mesistona and 41 reactance. Find (^) Crossacarent in the seandaries on no.load.ib) the load shared by euch transfarmer Their areThere is an installation with two equal triphasic loads of 300 kVA each and a power factor of 0.9 lagging. When connecting a pure reactive element in parallel, the reactive power at the entrance of the installation is 150 kVARS, with a lagging power factor. We can say that: a) A bank of reactors was connected and the fp deteriorated. b) A capacitor bank was connected and the pf deteriorated. c) A bank of reactors was connected and the fp improved. d) A capacitor bank was connected and the pf improved. e) None of the above
- Two relays each with 20-ohm resistance and 0.16-henry inductance are connected in series. What is the equivalent impedance?a. 20 + j102.2 ohms c. 20 + j95.32 ohmsb. 20 + j120.63 ohms d. 10 + j25.32 ohms128, An equipment has an impedance 0.9 p.u. to a base of 20 MVA, 33 kV. To the base of 50 MVA, 11 kV, the p.u. impedance will be (a) 4.7 (c) 0.9 (b) 20.25 (d) 6.75In the figure, bus 1 is the reference bus, V1 = 1.06 p.u and the angle is 0.. A load with active power= 100 MW and reactive power = 50 Mvar is connected to bus 2. The line impedance is z12 = 0.12 + j0.16 p.u on a base of 100 MVA. Start with an initial estimate of |V2|0) = 1.0 p.u and 820) = 0•. Find |V2| () (one iteration). 100 MW 212 = 0.12 + j0.16 ++ 50 Mvar Vị = 1.0/0° О а. |V2| (1) = 0.4 p.u. Ob. |V2| (1) = 0.5 p.u. Oc. |V2| (1) = 0.7 p.u. d. (1) = 0.8 p.u. е. |V2| (1) = 0.6 p.u.
- Consider the system in the figure to the right. The Zbus for the system is given as follows: [j0.411 j0.310 j0.3541 Zbusj0.310 j0.446 j0.333 Lj0.354 j0.333 j0.450] j0.8 1.28/0 ele j0.2 vor j2.0 j0.5 m j0.4 m 2 a) Find the voltage at each bus. b) Find the current drawn by a capacitor having a reactance of 5.0 PU connected from bus 3 to the reference. c) Find the change in voltage at each bus when the capacitor is connected at bus 3. d) Find the voltage at each bus after connecting the capacitor. j1.0 1.20/30°The Full-looad and No-load of a regulator are 5.2V and 5.3V, respectively. Then the % load regulation is а. 0.1% b. 2.63% C. 1.92% d. 5.3%j0.25 For the two coupled branches shown above, Ya =-j0.5, Yb = -j1 & Ym = j0.25. Using Equivalent Admittance, find the admittance located between nodes 2 & 3: O a. j0.25 O b. -j0.25 O c. None of these O d. -j1 O e. -j0.5
- The total power drawn by the two-impedance load in parallel is 26kW at 0.98 power factor lagging, it is being supplied by a 230-volts AC source. One of the loads (Load 1) takes 16kVA at 0.77 power factor lagging. What is the reactive power of the unknown impedance (Load 2)?In an installation there is a three-phase load of 300 kVA with a power factor of 0.8 behind, in parallel with a three-phase load of 150 kVA with a power factor of 0.6 ahead. A pure reactive element is connected in parallel, and a unity power factor is obtained at the power input. Indicate the reactant of the element, with a positive sign if it is a bank of reactors, or with a negative sign if it is a bank of capacitors. Just put the corresponding sign followed by the numerical value, without units. The numerical value must correspond to the three-phase kVARS. You can use integer values with no decimal places or up to two decimal placesIn an installation there is a three-phase load of 300 kVA with a power factor of 0.8 behind, in parallel with a three-phase load of 150 kVA with a power factor of 0.6 ahead. A pure reactive element is connected in parallel, and a unity power factor is obtained at the power input. Indicate the reactant of the element, with a positive sign if it is a bank of reactors, or with a negative sign if it is a bank of capacitors. Just put the corresponding sign followed by the numerical value, without units. The numerical value must correspond to the three-phase kVARS. You can use integer values with no decimal places or up to two decimal places