3. Use the given table below and the technique of coordinates to compute the traverse area and plot the graph of this balanced traverse data. (scale 1:100) BALANCED TRAVERSE DATA DISTANCE (m 46.05 COURSE BEARING AB N 3°30'E BC 41.92 N 0°30'W N 88°40'E S 23°30'E CD 25.02 DE 31.78 AE N 38°34'E 82.34

3. Use the given table below and the technique of coordinates to compute the traverse area and plot the graph of this balanced traverse data. (scale 1:100) BALANCED TRAVERSE DATA DISTANCE (m 46.05 COURSE BEARING AB N 3°30'E BC 41.92 N 0°30'W N 88°40'E S 23°30'E CD 25.02 DE 31.78 AE N 38°34'E 82.34

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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2. Correct the survey data below for a closed traverse. LINE OBSERVED DIMENSIONS DISTANCE BEARING (m) АВ 319.27 N 86°46' E N 1°35' W S 78°50' ВС 551.35 CD 417.26 W DE 220.87 S 30°25' W EA 375.36 S 36°17' E
4 decimal places in final answer
1. Given the following tabulations are observed and calculated data for a traverse. Balance the latitudes and departures by the COMPASS RULE and compute for the area of the closed traverse by DOUBLE PARALLEL METHOD (DPD). Tip: Before you compute for the area of the closed traverse, you must first adjust the latitudes and departures. LINE DISTANCE AZIMUTH LATITUDES LATITUDES DEPARTURES DEPARTURES (-S) FROM SOUTH 99°45' 154°00' 242°30' 353°15' (+N) (+E) (-W) 357.20 m 183.18 430.05 AB 60.49 164.64 198.54 352.04 80.30 BC CD DA SUMS 381.46 49.97 425.18 422.23 423.70 422.23 431.43 432.34
A closed traverse has the following data in the table. Use transit rule in balancing the traverse. What is the linear error of closure? LINE LENGTH(m) BEARING АВ 430.05 N 62°30' E BC unknown S 6°45' E CD 357.20 unknown DA 183.18 N 26°00' W
Problem 1. Given in the tabulation below are notes for an open traverse. Determine the latitude and departure of each course and tabulate each computed values accordingly. COURSE AB BC CD DE EF FG DISTANCE 550.30 m 395.48 m 462.70 m 631.22 m 340.05 m 275.86 m BEARING N 28°10' E S 69°35' E S 27°50' E N 50°00' E S 27°05' E DUE EAST
II. DETERMINE THE AREA OF THE CLOSED TRAVERSE USING DOUBLE MERIDIAN DISTANCE (DMD) METHOD: LINES BEARING DISTANCES AB S 8°51' W 126.90 m BC N 18°51' W 90.20 CD N 37°27' E 110.80 DA S 11°24' 31.72" W 54.55
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The data in the table below is for a closed-polygon traverse. Course Azimuth Length (m) Interior Angles AB 75°14'47" 519.674 A = 12°25'31" 455.265 B=48°19'25" 433.426 C = 126°37'24" 425.558 BC CD DE D = 46°03'36" 109.434 E = 306° 34'19" EA Part A Compute the preliminary azimuths. AZAB = 57°14'47", Azpc = 303° 34'09", AzcD = 250°11'30". AZDE = 116° 15'03". AZEA = 242° 49'19" AZAB = 75°00'47", Azpc = 303° 00'09", AZCD = 250°00'30", AZDE=116°00'03", AZEA = 242°00'19" AZAB = 75°14'47", AZBC = 313° 34'09", AzcD = 25°11'30", AZDE = 116° 10'00". AZEA = 224°49′19" AZAB = 75°14'47". AzBc = 303° 34'09", Azcp=250°11'30". AZDE = 116°15'03". AZEA = 242° 49'19" Submit Previous Answers ✓ Correct Part B Compute the unadjusted departures. Express your answers in meters to six significant figures and separated by commas. IVD ΑΣΦΠ Vec 6 X Incorrect; Try Again; ? AB. BC. CD. DE. EA= 502.304, 308.33, -407.578,381.998,- 97.061 m, mn, m, mn, m
I. TRANSIT RULE. Given in the accompanying tabulation are the observed data for a traverse obtained from a transit- tape survey. De- termine the latitudes and departures of each course and balance these quantities by employing the transit rule. Tabulate values accordingly. COURSE LENGTH AB BC CD 495.85m 850.62 855.45 AZIMUTH FROM NORTH 5°30' 46 02' 112°22' COURSE LENGTH 1,020.87m 1,117.26 660.08 DE EF FA AZIMUTH FROM NORTH 167°35' 263 44' 304°51' 2. ADJUSTMENT OF LENGTHS AND AZIMUTHS. Given the observed and calculated data in Problem No. I. Determine the adjusted length and adjusted azimuth (reckoned from north) of each course and tabulate values accordingly.
Given the following data for closed traverse, determine the following: