3. Use the following equilibria at 500 K to determine the values of Kp and Kp for the missing reaction. How many of the reactions as written are product favored? 2 CH4 (g) C2H6 (g) + H₂ (g) CH3OH (g) + H₂(g) CH4 (g) + H₂O (9) 2 CH3OH (g) + H₂ (g) C₂H6 (g) + 2 H₂0 (g) Kc = 9.5 x 10-13 Kc = 2.8 x 10-21 Kp = ?

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3. Use the following equilibria at 500 K to determine the values of Kp and Kp for the missing reaction. How
many of the reactions as written are product favored?
2 CH4 (9)
C2H6 (g) + H₂ (g)
CH4 (9) + H₂0 (9) CH3OH (g) + H₂ (g)
2 CH3OH (g) + H2 (g) C2H6 (g) + 2 H₂0 (g)
Kc = 9.5 x 10-13
Kc = 2.8 x 10-21
Kp = ?
Transcribed Image Text:3. Use the following equilibria at 500 K to determine the values of Kp and Kp for the missing reaction. How many of the reactions as written are product favored? 2 CH4 (9) C2H6 (g) + H₂ (g) CH4 (9) + H₂0 (9) CH3OH (g) + H₂ (g) 2 CH3OH (g) + H2 (g) C2H6 (g) + 2 H₂0 (g) Kc = 9.5 x 10-13 Kc = 2.8 x 10-21 Kp = ?
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