Certainly! Here is the transcription for an Educational website:---### Equilibrium Calculation for Decomposition of H₂SAt a certain temperature, the equilibrium constant $ K_p $ for the decomposition of hydrogen sulfide (H₂S) is 0.873.\[ H_2S(g) \rightleftharpoons H_2(g) + S(g) \]Initially, only H₂S is present at a pressure of 0.118 bar in a closed container. What is the total pressure in the container at equilibrium?**Equilibrium Calculation:**\[ P_{total} = \] _______ bar---Explanation:1. **Chemical Equation:** The reaction involves the decomposition of hydrogen sulfide gas (H₂S) into hydrogen gas (H₂) and sulfur gas (S). This process is reversible and reaches equilibrium.2. **Given Value:** The equilibrium constant $ K_p $ for this reaction is provided as 0.873.3. **Initial Condition:** The initial pressure of H₂S in the container is 0.118 bar.4. **Objective:** Determine the total pressure in the container once the system reaches equilibrium.The linear equation implies that as H₂S decomposes, the partial pressures of the products (H₂ and S) and reactant (H₂S) will adjust until the equilibrium constant expression is satisfied. Use the initial pressure and the equilibrium constant to solve for the equilibrium pressures and subsequently the total pressure.### Step-by-Step Approach:1. **Write the expression for $ K_p $:**\[ K_p = \frac{P_{H_2} \cdot P_S}{P_{H_2S}} \]2. **Assign variables** for changes in partial pressures at equilibrium:Let the change in pressure of H₂S be $ -x $ bar (it decreases as it decomposes), then the pressures of H₂ and S will both be $ +x $ bar (they increase as they are produced).3. **Set up the equilibrium pressures:**\[ P_{H_2S} = 0.118 - x \]\[ P_{H_2} = x \]\[ P_S = x \]4. **Substitute these expressions into the $ K_p $ equation:**\[ 0.873 = \frac{x \cdot x}{0.118 - x} \]5. **

We have given the Kp for decomposition of H2S Kp = 0.873 Initial concentration of H2S = [H2S] =…

At a certain temperature, the K, for the decomposition of H,S is 0.873. H,S(g) = H,(g)+S(g) Initially, only H,S is present at a pressure of 0.118 bar in a closed container. What is the total pressure in the container at equilibrium? bar Protal =

At a certain temperature, the K, for the decomposition of H,S is 0.873. H,S(g) = H,(g)+S(g) Initially, only H,S is present at a pressure of 0.118 bar in a closed container. What is the total pressure in the container at equilibrium? bar Protal =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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