Answered: 3. Use Gauss's law to calculate the… | bartleby

Related questions

Question

3. Use Gauss's law to calculate the electric field (magnitude and direction) at a radial distance of
5 cm due to a solid insulating sphere with a radius 3 cm. The total charge of the sphere is +5 µC
and the charge is uniformly distributed throughout the insulating sphere (charge density, p =
Q/V).
5 cm
3 cm
E = $Ē· dÃ = ¹in Gauss's Law
€0

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

1 - Your answer is partially correct. Two spherical shells have a common center. A-3.00 x 106 C charge is spread uniformly over the inner shell, which has a radius of 0.050 m. A +5.50 x 106 C charge is spread uniformly over the outer shell, which has a radius of 0.15 m. Find the magnitude and direction of the electric field at a distance (measured from the common center) of (a) 0.20 m, E = i 562 (b) 0.10 m, E = 2.04E-5 (c) 0.025 m. E = 0 N/C V N/C ♥ N/C V radially outward radially inward no direction
6. a non-conducting rod of length L has a charge of -q which is uniformly distributed across its length. (a) What is the linear charge density of the rod? (b) What is the electric field at point P which is still in the straight line connecting the non-conducting material, the distance x from the end of the rod?
2. Two point charges are placed on XY plane such that +2C charge at the origin and -4C charge on the X axis at X= 4 m. Label electric field due to each charge on the y axis at y= -3 m with arrowheads as electric field due to +2C as E1 and electric field due to - 4C as E2. Label the direction of net electric field as E with another arrowhead.
27. A small sphere with a charge of -0.60 µC is placed in a uniform electric field of magnitude 1.2 x 10° N/C pointing to the west. What is the magnitude and direc- tion of the electric force on the sphere?
2. Two charged nested conducting spheres are pictured below. The inner sphere (radius r=5 cm) carries a charge of q=100 nC. The outer sphere has an inner radius r= 10 cm and outer radius of r=12.5 cm. The charge on the outer sphere is -300 nC. a) Use Gauss's law to determine the electric field in the following regions: r12.5cm
Q3) Two point charges (Q = + 5.0 µC and Q2 = – 2.0 µ C) are held in place along the x-axis. Q, is at x1 = - 3.0 cm and Q, is at x2 = + 2.0 cm. a) Determine the electric field at (x, y) = (0,4.0 cm) in SI units. Represent your answer as a vector. Start with drawing a picture and setting up an appropriate coordinate system. b) Determine in what region along the x-axis it's possible for the electric field to be zero. There are three distinct regions: -o < x < x1, X1 < x < x2, and x2 < x < ∞ (this excludes x → ±∞ since the electric field is zero there). c) Now that you know in what region it's possible for the electric field to be zero, write out an expression you could solution to find exactly where this location is. Note: you DON'T have to solve it. d) Another charge (Q3 Newtons? Represent your answer as a vector. Hint: no need to apply Coulomb's law to Q3, you already know the electric field at this point. 4.0 µ C) is now placed at (x, y) = (0,4.0 cm). What is the net force on this…