3. Toroid a) A toroid is formed by winding a wire which carries current I with N turns. The toroid has a mean radius R, and a cross-section radius r. which is smaller than R. Using Ampere's law, derive an expression for B inside the toroid as the funciton of radial distance r which is the distance from the center of the toroid. Again, draw a figure with an amperian loop, direction of the path, and the direction of the magnetic field. Toroid R mean radius r = cross-section radius rc R N = 2000, I = 2A, R = 20 cm, rc = 6 cm for part b) and c) = 5500. Find the b) Inside the toroid is filled with annealed iron with Xm magnitude of the magnetization at r = R. c) Find the magnitude of the total magnetic field at r = R +/2 of the annealed iron filled toroid.
3. Toroid a) A toroid is formed by winding a wire which carries current I with N turns. The toroid has a mean radius R, and a cross-section radius r. which is smaller than R. Using Ampere's law, derive an expression for B inside the toroid as the funciton of radial distance r which is the distance from the center of the toroid. Again, draw a figure with an amperian loop, direction of the path, and the direction of the magnetic field. Toroid R mean radius r = cross-section radius rc R N = 2000, I = 2A, R = 20 cm, rc = 6 cm for part b) and c) = 5500. Find the b) Inside the toroid is filled with annealed iron with Xm magnitude of the magnetization at r = R. c) Find the magnitude of the total magnetic field at r = R +/2 of the annealed iron filled toroid.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter31: Gauss’s Law For Magnetism And Ampère’s Law
Section: Chapter Questions
Problem 46PQ
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
Transcribed Image Text:3. Toroid
a)
A toroid is formed by winding a wire which carries current I with N turns. The
toroid has a mean radius R, and a cross-section radius r. which is smaller than R.
Using Ampere's law, derive an expression for B inside the toroid as the funciton
of radial distance r which is the distance from the center of the toroid. Again,
draw a figure with an amperian loop, direction of the path, and the direction of
the magnetic field.
Toroid
R mean radius
r = cross-section radius
rc
R
N = 2000, I = 2A, R = 20 cm, rc
=
6 cm for part b) and c)
= 5500. Find the
b) Inside the toroid is filled with annealed iron with Xm
magnitude of the magnetization at r = R.
c) Find the magnitude of the total magnetic field at r = R +/2 of the annealed
iron filled toroid.
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