3. The vector current density is given as J = (4/r²) cose ar + 20e-2r sine ae - rsinecos ao at r = 3,0 = 0, 0 = π

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Number 3
2. A certain homogenous slab of lossless
dielectric material is characterized by an electric
susceptibility of 0.12 and carries a uniform
electric flux density within it of 1.6 nC/m².
mmmm
Find:
a. E
b. P
c. The average dipole moment if there are 2 x
109 dipoles per m³
3. The vector current density is given as J = (4/r²)
cose ar + 20e-2r sine ae - rsin cosØ aº at r = 3, 0
= 0, 0 = π
Transcribed Image Text:2. A certain homogenous slab of lossless dielectric material is characterized by an electric susceptibility of 0.12 and carries a uniform electric flux density within it of 1.6 nC/m². mmmm Find: a. E b. P c. The average dipole moment if there are 2 x 109 dipoles per m³ 3. The vector current density is given as J = (4/r²) cose ar + 20e-2r sine ae - rsin cosØ aº at r = 3, 0 = 0, 0 = π
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